如何在Java中按其元素大小对ArrayList排序? [英] How to sort an ArrayList by its elements size in Java?

问题描述

所以我有一个List<String> L1 = new ArrayList<>()，具有以下字符串作为元素:

So I have a List<String> L1 = new ArrayList<>() with the following strings as elements:

• l，l，u，u.
• r，u，d，l，d，l，u.
• l，u，d，r，r，r，r，r，u，d.
• l，你.
• l，u，r.

如何按元素的大小对list进行排序，以便在最终状态L1中应如下所示:

How do I sort the list by its element's size so that in the final state L1 should be like this:

• l，你.
• l，u，r.
• l，l，u，u.
• r，u，d，l，d，l，u.
• l，u，d，r，r，r，r，r，u，d.

我尝试使用Collections.sort，但是按字母顺序排序，这显然不是我想要的.

I have tried using Collections.sort, but that sorts alphabetically, which is obviously not what I want.

推荐答案

我认为您正在寻找的是

I think what you are looking for is Collections.sort(java.util.List, java.util.Comparator). With it you can specify a custom Comparator that compares the strings based on length instead of alphabetical relationship.

类似这样的东西:

List<String> stringList = new ArrayList<String>();

// Fill the list

Comparator<String> stringLengthComparator = new Comparator<String>()
    {
        @Override
        public int compare(String o1, String o2)
        {
            return Integer.compare(o1.length(), o2.length());
        }
    };

Collections.sort(stringList, stringLengthComparator);

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