如何在python 3中的任意列表中找到缺失的数字? [英] How to find the missing numbers in an arbitrary list in python 3?

问题描述

我正在尝试在任意列表中找到缺失的数字.在有序列表中，我的代码可以正常工作，但是在任意列表中，则不起作用.这是我的代码:

I am trying to find the missing numbers in an arbitrary list. In an ordered list my code works fine, but in an arbitrary list in doesn't work. This is my code:

a = [10,12,13,8]
b = [x for x in range(a[0], a[-1] + 1)]
a = set(a)
print(list(a ^ set(b)))

输出为:

[8, 10, 12, 13]

但是对a进行排序时，输出结果很好:

But when a is sorted, the output comes out fine:

[9,11]

我的代码有什么问题，我该如何解决? PS.我知道我可以对列表进行排序，并解决问题，但我也希望它也适用于任意列表.

What's wrong in my code and how can i fix it? PS. I know i can just sort the list and get the problem fixed but i want it to work on an arbitary list as well.

推荐答案

这是怎么回事:

a = [10, 12, 13, 8]
b = set(range(min(a), max(a)+1))
print(set(a).symmetric_difference(b))

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