随机播放列表并返回副本 [英] Shuffle a list and return a copy

问题描述

我想改组数组，但是我发现的只是之类的方法，来自

I want to shuffle an array, but all I find was method like random.shuffle(x), from Best way to randomize a list of strings in Python

我可以做类似的事情

import random
rectangle = [(0,0),(0,1),(1,1),(1,0)]
# I want something like
# disorderd_rectangle = rectangle.shuffle

现在我只能逃脱

disorderd_rectangle = rectangle
random.shuffle(disorderd_rectangle)
print(disorderd_rectangle)
print(rectangle)

但是它返回

[(1, 1), (1, 0), (0, 1), (0, 0)]
[(1, 1), (1, 0), (0, 1), (0, 0)]

因此，original array也已更改.我如何只创建另一个改组的array，而不更改原始的array?

So the original array is also changed. How can I just create another shuffled array without changing the original one?

推荐答案

这里的人们建议使用深度复制，这肯定是一个过大的杀伤力.您可能不介意列表中的对象相同，而只是想改变它们的顺序.为此，列表直接提供浅表复制.

People here are advising deepcopy, which is surely an overkill. You probably don't mind the objects in your list being same, you just want to shuffle their order. For that, list provides shallow copying directly.

rectangle2 = rectangle.copy()
random.shuffle(rectangle2)

关于您的误解:请阅读 http://nedbatchelder.com/text/names.html#no_copies

About your misconception: please read http://nedbatchelder.com/text/names.html#no_copies

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