如何为二维列表编号? [英] How to number a 2 dimensional list?

问题描述

我将这些列表包含在我要编号的列表中.我也有两个变量，行和列，它们被当作输入.

I have these lists inside a list that I am trying to number. I also have two variables, row and column, which are taken as input.

lst = row*[column*[0]]

这将使列表内的列表充满零，因此，如果row = 6和column = 10，则看起来像这样:

This makes lists inside a list that are filled with zeros, so if row = 6 and column = 10, it would look like:

[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],    
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],   
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],   
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],  
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],  
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]] 

如何更改它，使其看起来像这样:

How can I change it so it looks like this:

[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10],   
[11, 12, 13, 14, 15, 16, 17, 18, 19, 20],     
[21, 22, 23, 24, 25, 26, 27, 28, 29, 30],    
[31, 32, 33, 34, 35, 36, 37, 38, 39, 40],     
[41, 42, 43, 44, 45, 46, 47, 48, 49, 50],     
[51, 52, 53, 54, 55, 56, 57, 58, 59, 60]]

谢谢！

推荐答案

我认为这将是最"pythonic"的方式:

I think this would be the most "pythonic" way:

from pprint import pprint

rows = 6
cols = 10

lst = [[(j*cols+i) for i in range(1,cols+1)] for j in range(rows)]

pprint(lst)

输出:

[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10],
 [11, 12, 13, 14, 15, 16, 17, 18, 19, 20],
 [21, 22, 23, 24, 25, 26, 27, 28, 29, 30],
 [31, 32, 33, 34, 35, 36, 37, 38, 39, 40],
 [41, 42, 43, 44, 45, 46, 47, 48, 49, 50],
 [51, 52, 53, 54, 55, 56, 57, 58, 59, 60]]

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