Python将文本文件中每行的最后一个数字放入列表中 [英] Python take the last number of each line in a text file and make it into a list

问题描述

我只想每行的最后一个数字.

I just want the last number of each line.

with open(home + "/Documents/stocks/" + filePath , newline='') as f:
stockArray = (line.split(',') for line in f.readlines())
    for line in stockArray:
        List = line.pop()
        #print(line.pop())
        #print(', '.join(line))
else:
    print("Finished")

我尝试使用line.pop()获取最后一个元素，但仅从一行开始获取它?如何从每一行中获取并将其存储在列表中?

I tried using the line.pop() to take the last element but it only takes it from one line? How can I get it from each line and store it in list?

推荐答案

您可能只想要以下内容:

You probably just want something like:

last_col = [line.split(',')[-1] for line in f]

对于更复杂的csv文件，您可能需要查看标准库中的csv模块，因为它将正确处理字段引用等.

For more complicated csv files, you might want to look into the csv module in the standard library as that will properly handle quoting of fields, etc.

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