计算嵌套列表中球队的获胜次数 [英] Counting the number of wins for teams in a nested list

问题描述

我编写了一些代码，试图计算足球队赢得比赛的次数.将比赛放置在嵌套列表中，其中每个子列表分别包含两支球队的名称及其比赛得分.

I have written some code that I'm trying to use in order to calculate how many times a football team have won a match. The matches are placed into a nested list where each sub list contains the names of two teams and their scores for the game respectively.

L = [['Patriots', 'Giants', '3', '1'], ['Steelers', 'Patriots', '1', 2'], ['Giants', 'Steelers', '3', '5']]

但是，该列表更大，并且包含更多参加比赛的足球队.

However the list is much larger and contains more football teams who played in matches.

我已经有了一个最终列表，其中包含每个团队的名称以及他们参加的比赛次数，这些都是我成功计算出的.

I already have a final List which contains the name of each team and also the number of games they have played, which I calculated successfully.

finalList = [['Patriots', 7], ['Giants', 3], ['Steelers', 8]]

我希望输出像这样:

finalList = [['Patriots', 7, 2], ['Giants', 3, 0], ['Steelers', 8, 1]]

因为爱国者队打了7场比赛，赢得了两场比赛，巨人队打了3场，赢得了零场比赛，而钢人队打了8场，赢得了一场比赛.

because the Patriots played 7 games and won two games, Giants played 3 games and won zero games and Steelers played 8 games and won one game.

到目前为止，这是我的代码，对于某些比赛，它没有给我正确的结果.它也不会对计数求和，因此只附加一个数字1和0，如下所示:

This is my code so far, which doesn't give me the correct results for some of the matches. It also does not sum the counts so it just appends a number of 1's and 0's like this:

[['Giants', 5, 1, 0, 1]]

我的代码:

for i in L:
    countLeft = 0
    countRight = 0
    if i[2]>i[3]:
        countLeft += 1
    elif i[3]>i[2]:
        countRight += 1
        for k in finalList:
            if i[0]==k[0]:
                k.append(countLeft)
            elif i[1]==k[0]:
                k.append(countRight)
print(finalList)

我也不允许在我的代码中使用任何词典！

I am also not allowed to use any dictionaries in my code!!

推荐答案

尝试以下操作:

for k in finalList:
    k.append(0)

for i in L:
    if int(i[2]) > int(i[3]):
            for k in finalList:
                    if k[0] == i[0]:
                            k[2]+=1
    elif int(i[3]) > int(i[2]):
            for k in finalList:
                    if k[0] == i[1]:
                            k[2]+=1

---

>>> finalList
[['Patriots', 7, 2], ['Giants', 3, 0], ['Steelers', 8, 1]]
>>> 

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