计算嵌套mongodb文档中的出现次数并保留组 [英] Count occurrences in nested mongodb document and keeping group
问题描述
我有这些文件:
[
{
"question": 1,
"answer": "Foo"
},
{
"question": 1,
"answer": "Foo"
},
{
"question": 1,
"answer": "Bar"
},
{
"question": 2,
"answer": "Foo"
},
{
"question": 2,
"answer": "Foobar"
}
]
在后端(php)中,我需要获取答案的分区,例如:
And in my backend (php) I need to get the repartition of answers, something like:
-
问题1:
Question 1:
- "Foo":2/3
- 酒吧":1/3
问题2:
- "Foo":1/2
- "Foobar":1/2
目前,我只想运行mongo查询以实现此结果:
For now I just want to run a mongo query in order to achieve this result:
[
{
"question": 1,
"answers": {
"Foo": 2,
"Bar": 1
}
},
{
"question": 2,
"answers": {
"Foo": 1,
"Foobar": 1
}
}
]
这是我想出的:
db.getCollection('testAggregate').aggregate([{
$group: {
'_id': '$question',
'answers': {'$push': '$answer'},
}
}
]);
它返回:
{
"_id" : 2.0,
"answers" : [
"Foo",
"Foobar"
]
},{
"_id" : 1.0,
"answers" : [
"Foo",
"Foo",
"Bar"
]
}
现在我需要对Answers字段执行$ group操作以计算出现的次数,但是我需要按问题保留group,但我不知道该怎么做.有人可以帮我吗?
And now I need to to a $group operation on the answers field in order to count the occurences, but I need to keep the group by question and I do not know how to do it. Could someone give me a hand?
推荐答案
您可以使用以下聚合.
按问题和答案分组以获取合并计数,然后按问题分组以获取答案及其计数.
Group by both question and answer to get the count for combination followed by group by question to get the answer and its count.
db.getCollection('testAggregate').aggregate([
{"$group":{
"_id":{"question":"$question","answer":"$answer"},
"count":{"$sum":1}
}},
{"$group":{
"_id":"$_id.question",
"answers":{"$push":{"answer":"$_id.answer","count":"$count"}}
}}
]);
您可以使用以下代码在3.4中获取所需的格式.
You can use below code to get the format you want in 3.4.
将$group
键更改为k和v,后跟 $addFields
与 $arrayToObject
将数组转换为命名键值对.
Change $group
keys into k and v followed by $addFields
with $arrayToObject
to transform the array into named key value pairs.
db.getCollection('testAggregate').aggregate([
{"$group":{
"_id":{"question":"$question","answer":"$answer"},
"count":{"$sum":1}
}},
{"$group":{
"_id":"$_id.question",
"answers":{"$push":{"k":"$_id.answer","v":"$count"}}
}},
{"$addFields":{"answers":{"$arrayToObject":"$answers"}}}
]);
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