MongoDB 嵌套组? [英] MongoDB nested group?

问题描述

我正在尝试在 mongodb 中实现嵌套组查询，但在尝试添加外部组时遇到了困难.鉴于以下(简化的)数据文档:

<代码>{时间戳":ISODate(),类别":电影"，"term" : "我的电影"}

我正在尝试获得所有类别的列表，并且在类别中应该有最多的术语.我希望我的输出是这样的:

<预><代码>[{ 类别:电影"，条款:[ { 术语:电影 1"，总计:5000 }，{ 术语:电影 2"，总计:200 } ... ]},{ 类别:体育"，条款:[ { 术语:足球 1"，总计:4000 }，{ 术语:网球 2"，总计:250 } ... ]},]

我的内部组"如下图所示，将获得所有类别的前 5 名:

db.collection.aggregate([{ $match : { "timestamp": { $gt: ISODate("2014-08-27") } } },{ $group : { _id : "$term", total : { $sum : 1 } } },{ $sort : { total : -1 } },{ $limit: 5 }]);//输出:{_id":电影 1"，总计":943 }{_id":电影 2"，总计":752 }

我将如何实施外部团体"?

此外，有时上述聚合]ion 会返回空值(并非所有文档都具有 term 值).如何忽略空值?

提前致谢

解决方案

在这种情况下，您将需要两个组.第一组生成一个文档流，每个术语和类别一个文档:

 { $group : {_ID :  {类别:$类别"，术语:$term"，},总计:{ $sum :1}}}

然后，第二组将使用 $push 运算符将类别合并到一个数组中:

 { $group : {_id : "$_id.category",条款:{$推:{term:"$_id.term",总计:$总计"}}}}

I'm trying to implement a nested group query in mongodb and I'm getting stuck trying to add the outer group by. Given the below (simplified) data document:

{
  "timestamp" : ISODate(),
  "category" : "movies",
  "term" : "my movie"
}

I'm trying to achieve a list of all categories and within the categories there should be the top number of terms. I would like my output something like this:

[
 { category: "movies", 
   terms: [ { term: "movie 1", total: 5000 }, { term: "movie 2", total: 200 } ... ]
 },
 { category: "sports", 
   terms: [ { term: "football 1", total: 4000 }, { term: "tennis 2", total: 250 } ... ]
 },
]

My 'inner group' is as shown below, and will get the top 5 for all categories:

db.collection.aggregate([
    { $match : { "timestamp": { $gt: ISODate("2014-08-27") } } },
    { $group : { _id :  "$term", total : { $sum : 1 } } },
    { $sort : { total : -1 } },
    { $limit: 5 }
]);

// Outputs:
{ "_id" : "movie 1", "total" : 943 }
{ "_id" : "movie 2", "total" : 752 }

How would I go about implementing the 'outer group'?

Additionally sometimes the above aggregate]ion returns a null value (not all documents have a term value). How do I go about ignoring the null values?

thanks in advance

解决方案

You will need two groups in this case. The first group generates a stream of documents with one document per term and category:

 { $group : { 
      _id :  { 
        category: "$category",
        term: "$term",
      },
      total: { $sum : 1 } 
   }
 }

A second group will then merge all documents with the same term into one, using the $push operator to merge the categories into an array:

 { $group : { 
      _id :  "$_id.category",
      terms: { 
          $push: { 
              term:"$_id.term",
              total:"$total"
          }
      }
   }
 }

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