在此链表方法中,我尝试按排序顺序添加项目,但出现空指针异常 [英] In this linked list method I try to add a item in sorted order, but I am getting a null pointer exception
本文介绍了在此链表方法中,我尝试按排序顺序添加项目,但出现空指针异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
public void addNode(Car newCarEntry){
ListNode currentNode;
ListNode previousNode;
ListNode newNode = new ListNode(newCarEntry);
if (head == null || newCarEntry.isNewerThan(head.carItem)){
newNode.next = head;
head = newNode;
}else{
currentNode = head.next;
previousNode = head;
while(currentNode != null && !newCarEntry.isNewerThan(currentNode.carItem)){
currentNode = currentNode.next;
previousNode = currentNode;
}
newNode.next = currentNode;
newNode = previousNode.next;
}
}
推荐答案
前进指针的方式有误. 更改:
You have a mistake in the way you advance the pointers. Change:
currentNode = currentNode.next;
previousNode = currentNode;
到
previousNode = currentNode;
currentNode = currentNode.next;
您使currentNode和previousNode都持有对同一对象的引用的方式,这不是您想要的.
Your way you make both currentNode and previousNode holding references to the same object, which is not what you want.
另外,您的最后一行应该是
Also your last line should be
previousNode.next = newNode;
入海
newNode = previousNode.next;
因为您不是以这种方式将新节点附加到列表中.
because you are not attaching the new node to the list this way.
这篇关于在此链表方法中,我尝试按排序顺序添加项目,但出现空指针异常的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文