在bash中创建一个锁定文件，以避免重复执行 [英] create a lock file in bash to avoid duplicate execution

问题描述

我对bash不太好，我一直在修改代码以创建锁定文件，因此如果第一个过程尚未完成，cron不会再次执行.

I'm not very good on bash I've been modifying a code to create a lock file so a cron don't execute a second time if the first process hasn't finish.

LOCK_FILE=./$(hostname)-lock
(set -C; : > $LOCK_FILE) 2> /dev/null
if [ $? != "0" ]; then
   echo "already running (lock file exists); exiting..."
exit 1
fi

trap 'rm $LOCK_FILE' INT TERM EXIT

当我第一次运行它时，我得到的消息已经在运行，就好像文件已经存在一样.

when I run it for the first time I get the message already running as if the file already existed.

也许我想念一些东西

推荐答案

#!/bin/sh

(
  # Wait for lock on /tmp/lock

  flock -x -w 10 200 || exit 127 # you can use or not use -w

  #your stuff here

) 200> /tmp/lock

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