制作一个聪明的听众发出通知，以避免code重复无处不在 [英] Making a smart listeners notifier to avoid code duplication everywhere

问题描述

注意：的code是线程安全的，换句话说，单线程的。只有我可以从听众的名单中删除自己。

ATTENTION: The code is thread-safe, in other words, single-threaded. Only I can remove myself from the list of listeners.

我有1000个不同听众的ArrayList，我不得不通知与code象下面这样：

I have 1000 different ArrayLists of listeners that I have to notify with code like below:

protected void onFlushed() {
    int size = listeners.size();
    for (int i = 0; i < size; i++) {
        listeners.get(i).onFlushed();
        int newSize = listeners.size();
        if (newSize == size - 1) {
            size--;
            i--;
        } else if (newSize != size) {
            throw new ConcurrentModificationException("List was altered while iterating! oldSize=" + size + " newSize=" + newSize);
        }
    }
}

有一个聪明的方法来创建一个通知程序类，可以采取监听任何ArrayList中加上任何监听器方法，并执行下面的逻辑，我或我要重复code以上处处为每一个听众的方法？

Is there a smart way to create a Notifier class that can take any ArrayList of listeners plus any listener method and perform the logic below for me OR I have to duplicate the code above everywhere for every listener method?

我要求太多了从Java？ ：（

Am I asking too much from Java? :(

推荐答案

在当前的Java，有没有办法通过一个方法周围，你可以做一个函数式语言，但是你可以创建一个功能＆LT;域名，范围和GT; 接口，并通过周围对象实现该接口

In current Java, there is no way to pass a method around, as you might do in a functional language, but you can create a Function<Domain, Range> interface and pass around objects implementing that interface.

您可以考虑使用番石榴，它提供类似的东西功能成语和列表-COM prehension。

You might consider using Guava, which supplies something resembling functional idioms and list-comprehension.

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