如何从Logback中的Java堆栈跟踪中删除换行符? [英] How do I remove newline from Java stacktraces in logback?

问题描述

我正在尝试从Java堆栈跟踪中删除换行符.

I'm trying to remove newline from Java stacktraces.

我遵循的是logback模式-

I've following logback pattern -

<pattern>%d{HH:mm:ss.SSS} [%thread] %-5level %logger{36} - %replace(%msg){'\n', ''}%n</pattern>

我希望它能替换邮件中的换行符，但它不会这样做.我看到用换行符打印的堆栈跟踪.

I expect it to replace newlines in messages but it is not doing so. I see stacktraces printed out with newlines.

但是，如果我使用以下模式(仅用于测试目的)-

However, if I use following pattern (for testing purpose only)-

<pattern>%d{HH:mm:ss.SSS} [%thread] %-5level %logger{36} - %replace(%msg){'.*', 'x'}%n</pattern>

我发现消息已被替换为字符x，但是堆栈跟踪仍按原样打印.

I find that messages are getting replaced with character x but stack traces are still getting printed as is.

这使我相信logback对栈跟踪的处理是独立的. 我浏览了logback文档，该文档指出可以通过(％ex)引用堆栈交易记录.

This makes me believe that logback treats stacktraces indepdentantly. I've gone through the logback documentation it says that one can refer to stacktraes via (%ex).

但是，随后我只能使追加程序一次处于活动状态. 如何确保在堆栈跟踪中没有换行符?

But then, I can have only one pattern active at a time for the appender. How do I go about making sure that I don't get newline in stacktraces?

推荐答案

查看Logback格式化程序如何在Windows框上构建字符串后，我看到堆栈跟踪的每一行都包含\r\n，因此如果使用Windows，请尝试以下方法:

After looking at how Logback formatter builds the string on my Windows box, I saw that the stack trace contains \r\n for each new line, so if you are using Windows, try this instead:

<pattern>........ %replace(%ex){'[\r\n]+', '\\n'}%nopex%n</pattern>

说明:

• \r\n:起初我只尝试使用%replace(%ex){'\n', 'X'}，但随后在日志中输入了换行符，然后是'X'.相反，使用%replace(%ex){'[\r\n]+', ''}会删除所有出现的\r和\n.如果要显示字符串"\n"表示此处有新行，则可以在%replace第二个参数中添加'\\n'.

• \r\n : At first I tried with only %replace(%ex){'\n', 'X'} but then I had in the logs the new line character then a 'X'. Instead, using %replace(%ex){'[\r\n]+', ''} removes all occurrences of \r and \n. If you want to display the string "\n" to indicate that a new line was here, you can add '\\n' in the %replace second parameter.

%nopex:我不知道为什么，但是如果您在%ex上使用%replace，则Logback将第二个堆栈跟踪添加到您的条目中，这次包含所有新行.使用%nopex(请参阅文档)，它将通过伪造来抑制第二个堆栈使用没有任何%replace的实际堆栈.

%nopex : I don't know why, but if you use %replace on %ex, Logback adds a second stack trace to your entry, this time with all the new lines. Using %nopex (see documentation), it will suppress this second stack by faking the use of an actual stack without any %replace.

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