如何从ASCII文件的替换行中删除换行符 [英] How do I remove the line break from alternate lines in an ASCII file

问题描述

我有一个ASCII文件，其中包含以下数据

I have an ASCII file that contains data as follows

    459999XXX9998882      WTD CCD           3,500.00-         0.00         3,500.00-         0.00       0.00
       09/07/17  23:00:07   999999999999 000000000000 EONCO024 GTUR BR              AND PARDES  APIN
    459999XXX9998883      WTD CCD             400.00-         0.00           400.00-         0.00       0.00
       09/07/17  23:00:12   999999999999 000000000000 EOMCO015 P.G ROAD, ANNA HOT SECU  TLIN
    29999XXX99988829      INQ CCD               0.00          0.00             0.00          0.00       0.00
       09/07/17  23:00:41   999999999999 000000000000 EOMCO010 PUNA KUMBHARIA ROAD,   SUR        GJIN
    5459999XXX999888   INQ SAV               0.00          0.00             0.00          0.00       0.00    UNABLE TO PROC
       09/07/17  23:00:44   999999999999 000000000000 EONCO089 CTS NO 3985/5 ST STAND SOL      MHIN

我希望包含日期的行与上方的行联系起来. Essenatilly我想从奇数行中删除所有换行符.结果就是这样

I would like lines containing the dates to be contactenated to the line above it. Essenatilly I would like to remove all the line breaks from odd numbered lines. So the result is something like this

459999XXX9998882      WTD CCD           3,500.00-         0.00         3,500.00-         0.00       0.00 09/07/17  23:00:07   999999999999 000000000000 EONCO024 GTUR BR              AND PARDES  APIN
459999XXX9998883      WTD CCD             400.00-         0.00           400.00-         0.00       0.00 09/07/17  23:00:12   999999999999 000000000000 EOMCO015 P.G ROAD, ANNA HOT SECU  TLIN
29999XXX99988829      INQ CCD               0.00          0.00             0.00          0.00       0.00 09/07/17  23:00:41   999999999999 000000000000 EOMCO010 PUNA KUMBHARIA ROAD,   SUR        GJIN
5459999XXX999888      INQ SAV               0.00          0.00             0.00          0.00       0.00    UNABLE TO PROC 09/07/17  23:00:44   999999999999 000000000000 EONCO089 CTS NO 3985/5 ST STAND SOL      MHIN

我尝试了此处提供的解决方案，但然后它删除了所有换行符，从而形成了一行！将不胜感激.

I tried the solution provided here but then it removed all the linebreaks resulting in one single line! Would appreciate any ideas.

推荐答案

sed 'N;s/\n/ /' ip.txt 

• N将下一行添加到图案空间
• s/\n/ /将第一个换行符更改为空格(或任何分隔符)
• \n的用法可能取决于sed的实现.已在GNU sed
上进行了测试
• N add next line to pattern space
• s/\n/ / change first newline character to space (or whatever is the separator)
• Usage of \n might depend on sed implementation. This was tested on GNU sed

使用perl，如果行号为奇数，请更改换行符

With perl, change newline character if line number is odd

perl -pe 's/\n/ / if $.%2' ip.txt


也可以使用


Can also use

xargs -d'\n' -n2 -a ip.txt

• -d'\n'换行符作为分隔符
• -n2两行作为参数(空格用于合并它们)
• -d'\n' newline character as delimiter
• -n2 two lines together as argument (space is used to combine them)

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