我可以隐式刷新数据吗? [英] Can I flush data implicitly?

问题描述

是否有一种隐式刷新数据到输出流的方法?

Is there a way to implicitly flush data to an output stream?

#include <iostream>
#include <fstream>
using namespace std;

#define log logstream 

int main()
{
  ofstream logstream("test.log");

  log << "Test1" << 123 << endl;     // explicitly flushed
  log << "Test2" << 123;             // ?

  // Test2 not written, yet...

  cout << "Check log file..." << endl;
  int tmp;
  cin >> tmp;
}

我希望能够在不每次指定<< endl操纵器的情况下登录.

I would like to be able to log without specifying the << endl manipulator every time.

推荐答案

您可以使用 std::unitbuf .

You may use std::unitbuf.

log << std::unitbuf;

然后在每次插入时进行刷新.

And then flush would be done at each insertion.

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