每次cron作业运行时都有新的日志文件 [英] New log file every time cron job runs

问题描述

我已经弄清楚了如何使用>>将cron作业输出到日志文件并提供日志文件的路径. >>将日志信息附加到现有文件.我该如何做，以便cron作业每次运行时都创建一个新的日志文件? (即rsync.log，rsync(1).log，rsync(2).log-理想情况下，我希望日志的文件名类似于DD-MM-YY.log).

I have figured out how to output cron jobs to a log file using >> and providing a path to the log file. The >> appends log information to the existing file. How can I make it so the cron job creates a new log file every time it runs? (i.e. rsync.log, rsync(1).log, rsync(2).log -- ideally though I'd like the file name of the log to be something like DD-MM-YY.log).

我想要一个单独的日志文件，因此该日志文件不会太大，以及是否/当我们查看文件/文件夹是否已成功备份时(我在cron作业中运行rsync命令)我们不必梳理MASSIVE日志文件.

I want a separate log file so this one log file doesn't get so huge and if/when we go to look if a file/folder was successfully backed up (I'm running an rsync command in the cron job) we don't have to comb through a MASSIVE log file.

此外，将cron作业输出到日志文件时，没有时间/日期引用.我的第一个日志输出示例:

Additionally, when the cron job is outputted to the log file, there are no time/date references. Example of my first log output:

**sending incremental file list**
**sent 78 bytes  received 11 bytes  35.60 bytes/sec**
**total size is 0  speedup is 0.00**

就是这样.每次运行作业时，此日志文件上的时间戳都会不断更改，因此我们甚至无法得知通过rsync复制特定文件/文件夹的日期.如果每次cron作业运行时都有一个单独的日志文件，则可以打开创建该日志文件的特定日期的日志文件，并查看备份的内容.

That's it. The timestamp on this logfile will keep changing every time the job is run, so we wouldn't even be able to tell what day that particular file/folder was copied via rsync. If I had a separate log file for every time the cron job ran, I could just open the log file for the particular date that it was created and view what was backed up.

我当前的cronjob:

My current cronjob:

*/1 * * * * rsync -avz /home/me/test/ [e-mail]:test/ >>/home/me/cron_logs/homedir_backups/rsync.log 2>&1

出于测试目的，我仅将其设置为1分钟.最终，该操作只会每天在午夜运行.

I only have it set to 1 minute for testing purposes. Eventually this will only run daily at midnight.

推荐答案

如果您希望使用时间戳记日志，请添加格式化日期命令的字符串， 日期+％d％y％m表示日期月份的年份，数字格式.

If you want time stamped logs, you add the string of a formatted date command, date +%d%y%m for day month year in number format.

您可以使用反引号将字符串放入cron:

You can use backtick to put the string in the cron:

~$ /home/me/cron_log-`/bin/date +%d-%m-%y`

因此，文件名将带有当前日期.反引号表示运行此命令并将输出作为字符串放在这里".

So the file name will have the current date appended to it. The backtick says "run this command and put the output here as a string".

现在的问题是您的目录可能会很大，然后您必须编写一个简短的脚本来按时间删除它们.我有一个脚本，可以读取格式并保留X并删除其余的，但是大多数人只会使用"find"按时间删除较旧的内容，例如mtime> 1年的日志.

Now the problem is that your directory might get huge and then you have to write a short script to delete them by time. I have a script that reads the format and keeps X and deletes the rest but most people would just use "find" to delete by time older stuff, like logs that have mtime > 1 year.

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