如何在Linux/bash中为Shell脚本创建状态日志 [英] How to create status logs for shell script in Linux/bash

问题描述

我有一个shell脚本.我要向该脚本传递文件中的参数.该文件包含表名

I have a shell script. To this script I am passing arguments from a file. This file contains tables names

脚本运行正常.我可以对文件中的所有表执行命令.

The script is working fine. I am able execute the command for all the tables in the file.

shell script

#!/bin/bash

[ $# -ne 1 ] && { echo "Usage : $0 input file "; exit 1; }
input_file=$1

TIMESTAMP=`date "+%Y-%m-%d"`
touch /home/$USER/logs/${TIMESTAMP}.success_log
touch /home/$USER/logs/${TIMESTAMP}.fail_log 
success_logs=/home/$USER/logs/${TIMESTAMP}.success_log
failed_logs=/home/$USER/logs/${TIMESTAMP}.fail_log

#Function to get the status of the job creation
function log_status
{
       status=$1
       message=$2
       if [ "$status" -ne 0 ]; then
                echo "`date +\"%Y-%m-%d %H:%M:%S\"` [ERROR] $message [Status] $status : failed" | tee -a "${failed_logs}"
                #echo "Please find the attached log file for more details"
                #exit 1
                else
                    echo "`date +\"%Y-%m-%d %H:%M:%S\"` [INFO] $message [Status] $status : success" | tee -a "${success_logs}"
                fi
}

while read table ;do 
  sqoop job --exec $table > /home/$USER/logging/"${table}_log" 2>&1
done < ${input_file}

g_STATUS=$?
log_status $g_STATUS "Sqoop job ${table}"

我正在尝试收集脚本的status logs.

I am trying to collect the status logs for the script.

我想分别收集每个表的status logs.

I want to collect the status logs for each table individually.

我想要什么

2017-04-28 20:36:41 [ERROR] sqoop job table1 EXECUTION [Status] 2 : failed
2017-04-28 20:36:41 [ERROR] sqoop job table2 EXECUTION [Status] 2 : failed

我得到的是

如果最后一张表的脚本失败

If the script for last table fails

2017-04-28 20:38:41 [ERROR] sqoop job EXECUTION [Status] 2 : failed 

如果最后一个表的脚本成功，则

If the script for the last table is successful then

2017-04-28 20:40:41 [ERROR] sqoop job [Status] 0 : success    

我在做错什么，我应该做些什么改变才能获得理想的结果.

What am I doing wrong and what changes should I make to get desired results.

推荐答案

更改

while read table ;do 
  sqoop job --exec $table > /home/$USER/logging/"${table}_log" 2>&1
done < ${input_file}

g_STATUS=$?
log_status $g_STATUS "Sqoop job ${table}"

到

while read table ;do 
  sqoop job --exec $table > /home/$USER/logging/"${table}_log" 2>&1
  g_STATUS=$?
  log_status $g_STATUS "Sqoop job ${table}"
  # Any other command you want to run on using $table should be placed here
done < ${input_file}

while循环仅在while和done行中运行代码.因此，要记录所有表，您需要在while循环中运行记录.

The while loop only runs the code within the while and done lines. So to log for all tables, you need to run the logging inside the while loop.

此外，$table会在循环迭代中更改，因此要在所有表上运行的任何命令都需要在循环内运行.

Also, $table changes in iteration of the loop, so any command that you want to run on all tables, you need to run inside the loop.

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