网格中最大的产品 [英] Largest product in a grid
问题描述
我陷入了这个问题.我确实认为我有正确的解决方案,但是在将其提交到网站时,它不接受.
I'm stuck with this problem. I do think I've got the right solution but when submitting it to the website, it does not accept it.
我尝试通过打印所有可能的组合来调试它,它们都已完成(水平,垂直和对角线).数组也正确填充.我通过打印后对其进行了检查.
I tried debugging it by printing all the possible combinations and they're all done (horizontally, vertically and diagonally). The array is filled correctly also. I checked it by printing it after.
您知道问题可能在哪里吗?
Do you know where the problem may be?
相同的四个相邻数字的最大乘积是多少 是20×20网格中的方向(上,下,左,右或对角线)?
What is the greatest product of four adjacent numbers in the same direction (up, down, left, right, or diagonally) in the 20×20 grid?
String product =
"08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08 "
+ "49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00 "
+ "81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65 "
+ "52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91 "
+ "22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80 "
+ "24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50 "
+ "32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70 "
+ "67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21 "
+ "24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72 "
+ "21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95 "
+ "78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92 "
+ "16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57 "
+ "86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58 "
+ "19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40 "
+ "04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66 "
+ "88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69 "
+ "04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36 "
+ "20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16 "
+ "20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54 "
+ "01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48 ";
Scanner sc = new Scanner(product);
int[][] in = new int[20][20];
for (int i = 0 ; i < 20 ; i++){
for (int j = 0 ; j < 20 ; j++){
in[i][j] = sc.nextInt();
}
}
int max = Integer.MIN_VALUE;
int tmp = 0;
for (int i = 0 ; i < 20 ; i++){
for (int j = 0 ; j < 20 ; j++){
if (i < 17){
tmp = in[i][j] * in[i+1][j] * in[i+2][j] * in[i+3][j];
if (tmp > max) max = tmp;
}
if (j < 17){
tmp = in[i][j] * in[i][j+1] * in[i][j+2] * in[i][j+3];
if (tmp > max) max = tmp;
}
if (j < 17 && i < 17){
tmp = in[i][j] * in[i+1][j+1] * in[i+2][j+2] * in[i+3][j+3];
if (tmp > max) max = tmp;
}
}
}
System.out.println(max);
输出
51267216
推荐答案
您只需检查一条对角线,即朝右下角的那条对角线.
You only check one diagonal, namely the one that goes in the down-right direction.
向右走:
if (i < 17 && j > 2){
tmp = in[i][j] * in[i+1][j-1] * in[i+2][j-2] * in[i+3][j-3];
if (tmp > max) max = tmp;
}
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