pandas 中的元素级逻辑或 [英] Element-wise logical OR in Pandas

问题描述

我想要逐个元素的逻辑OR运算符.我知道或"本身不是我想要的.

I would like the element-wise logical OR operator. I know "or" itself is not what I am looking for.

我知道AND对应&而不是~.但是OR呢?

I am aware that AND corresponds to & and NOT, ~. But what about OR?

推荐答案

相应的运算符为|:

 df[(df < 3) | (df == 5)]

将按元素检查值是否小于3或等于5.

would elementwise check if value is less than 3 or equal to 5.

如果您需要执行此操作的功能，则可以 np.logical_or .对于两种情况，您可以使用

If you need a function to do this, we have np.logical_or. For two conditions, you can use

df[np.logical_or(df<3, df==5)]

或者，对于多种情况，请使用logical_or.reduce

Or, for multiple conditions use the logical_or.reduce,

df[np.logical_or.reduce([df<3, df==5])]

由于将条件指定为单独的参数，因此不需要括号分组.

Since the conditions are specified as individual arguments, parentheses grouping is not needed.

有关熊猫逻辑操作的更多信息，请参见此处.

More information on logical operations with pandas can be found here.

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