Python中位串的逻辑或 [英] Logical OR for Bit-string in Python

问题描述

我想做的是得到两个位字符串的逻辑或结果.例如:

What i want to do is have the result of logical OR for two bit-strings. For example:

    a='010010'
    b='000101'
    c=LOGIC_OR(a,b)
    c
    010111

我大多数时候遇到的错误是当我将'b'从字符串转换为二进制时，它会删除前导零.我使用过的其他方法将'a'和'b'转换为整数.通常，没有任何效果，将不胜感激.预先感谢

The error i encounter most of the time is when I convert 'b' from string to binary it removes leading zeros. Others methods i have used convert 'a' and 'b' to integers. Generally nothing is working and help would be much appreciated. Thanks in advance

推荐答案

以下是几种替代方法.

第三方 bitarray 库:

from bitarray import bitarray

a='010010'
b='000101'

logical_or_bitarray = bitarray(a) | bitarray(b)  # output: bitarray('010111')
logical_or_string = ''.join(map(str, map(int, logical_or_bitarray)))  # output: '010111'

Python字符串:-

Python strings:-

a='010010'
b='000101'

def compare_bits(A, B):
    c_1 = str(int(A) | int(B))
    c = (len(A) - len(c_1))*'0' + str(c_1)
    return c

compare_bits(a, b)

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