(Python)坚持跳过randint列表的总和的范围值 [英] (Python) Stuck on skipping range values for the sum of a randint list

问题描述

我需要用python编写一个程序，该程序可以从1-100生成十个随机数，并使用循环将其存储在列表中.然后，第二个循环应显示所述列表，然后计算偶数和奇数元素的总和以显示它们.到目前为止，这是我所拥有的，非常感谢您的帮助.谢谢

I need to make a program in python that generates ten random numbers from 1-100 that stores it in a list using a loop. Then a second loop should display said list, then calculate the sums of the even and odd elements to display them. This is what I have so far, any help is greatly appreciated. Thanks

import random

def main():
    numlist = [0] * 10

    for r in range(10):
        numlist[r] = random.randint(1,100)
    print(numlist)

    list_length = len(numlist)
    print('The number of elements in the list is', list_length)

更具体地说，这是我坚持的部分.我必须添加奇数元素和偶数元素的总和.我尝试过的每项工作都只给了我全部元素的总和.

More specifically this is the part I'm stuck on. I have to add the sums of the odd and then even elements. Every work around I've tryed has only given me the sum of the total elements.

    for x in range(0, 10, 2):
        numlist[x] = numlist 

    print('The Sum of the odd numbers is ', sum(numlist))


main()

推荐答案

import random
nums = [random.randint(1,100) for _ in range(10)]

您可以使用lambda和filter

You can use lambdas and filter

evenSum = sum(filter(lambda i : i%2 == 0, nums))
oddSum = sum(filter(lambda i : i%2, nums))

或进行一些快速帮助功能

Or make some quick helper functions

def isEven(x):
    return x % 2 == 0

def isOdd(x):
    return x % 2 == 1

evenSum = sum(filter(isEven, nums))
oddSum = sum(filter(isOdd, nums))

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