跳过python中range函数的值 [英] Skip over a value in the range function in python
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问题描述
通过一系列数字循环并跳过一个值的pythonic方式是什么?例如,范围是从0到100,我想跳过50。
编辑:
这是我正在使用的代码
为范围(0,len(list)):
x = listRow(list,i)
j在范围内(#0到len(list)不包括x#)
...
#创建一个不包含的范围如果x!= 50,则为$ 50
:
print i
#创建2个范围[0,49]和[51 ,100](Python 2)
在范围内(50)+范围(51,100):
print i
#创建一个迭代器并跳过50
xr = iter(xrange(100))
for i xr:
print i
if i == 49:
next(xr)
#只要继续在循环中,如果数字为50
(i)在范围内(100):
if i == 50:
continue
print i
What is the pythonic way of looping through a range of numbers and skipping over one value? For example, the range is from 0 to 100 and I would like to skip 50.
Edit: Here's the code that I'm using
for i in range(0, len(list)):
x= listRow(list, i)
for j in range (#0 to len(list) not including x#)
...
解决方案
You can use any of these:
# Create a range that does not contain 50
for i in [x for x in xrange(100) if x != 50]:
print i
# Create 2 ranges [0,49] and [51, 100] (Python 2)
for i in range(50) + range(51, 100):
print i
# Create a iterator and skip 50
xr = iter(xrange(100))
for i in xr:
print i
if i == 49:
next(xr)
# Simply continue in the loop if the number is 50
for i in range(100):
if i == 50:
continue
print i
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