如何将编号列表切成子列表 [英] How to slice numbered lists into sublists

问题描述

我打开了一个文件，并将readlines()和split()与正则表达式'\t'一起使用以删除TAB，结果显示在以下列表中:

I have opened a file and used readlines() and split() with regex '\t' to remove TABs and it has resulted into the following lists:

["1", "cats", "--,"]
["2", "chase", "--,"]
["3", "dogs", "--,"]
["1", "the", "--,"]
["2", "car", "--,"]
["3", "is", "--,"]
["4", "gray", "--,"]

现在，我想通过将索引[0]上的整数作为句子边界进行循环，将其提取并切成子列表，例如猫追狗"和汽车是灰色的".例如1-3子列表猫追狗"，然后继续计数1-4子列表汽车是灰色的"，依此类推，其余列表这样子，所以我得到子列表["the", "car", "is", "gray" ].我该怎么做?

Now I want to extract and slice this into sublists like "cats chase dogs" and "the car is gray" by looping the integers on index [0] as sentence boundaries. For instance 1 - 3 to sublist "cats chase dogs" and then continue counting 1 - 4 to sublist "the car is gray" and so on for the rest of the lists so I get sublists ["the", "car", "is", "gray" ]. How do I do this?

我已经试过了，但是出现错误:

I've tried this I'm but getting an error:

无法连接int + str

Can't concatenate int + str

在for循环中将"i"检测为字符串元素而不是整数:

Detecting "i" in the for loop as a string element instead of an integer:

with open(buffer, 'r') as f:
    words = []
    for line in f:
        items = line.split('\t')[:1]
        for i in items:
            while i>1:
                i = i+1
                print i

推荐答案

类似的东西:

from itertools import groupby

with open('yourfile') as fin:
    # split lines
    lines = (line.split() for line in fin)
    # group by consecutive ints
    grouped = groupby(enumerate(lines), lambda (idx, el): idx - int(el[0]))
    # build sentences from words in groups
    sentences = [' '.join(el[1][1] for el in g) for k, g in grouped]
    # ['cats chase dogs', 'the car is gray']

注意:这基于您的示例数据:

NB: This works based on your example data of:

example = [
    ["1", "cats", "--,"],
    ["2", "chase", "--,"],
    ["3", "dogs", "--,"],
    ["1", "the", "--,"],
    ["2", "car", "--,"],
    ["3", "is", "--,"],
    ["4", "gray", "--,"]
]

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