如何将列表中的连续元素拆分为子列表 [英] How to split consecutive elements in a list into sublists

问题描述

我有以下列表:

indices_to_remove: [0,1,2,3,..,600,800,801,802,....,1200,1600,1601,1602,...,1800]

我基本上有3个连续索引的子集:

I have basically 3 subsets of consecutive indices:

1. 0-600
2. 800-1200
3. 1600-1800

我想创建3个不同的小列表，这些小列表将仅包含连续的数字.

I would like to create 3 different small lists that will include only consecutive numbers.

预期结果:

indices_to_remove_1 : [0,1,2,3,....,600]
indices_to_remove_2 : [800,801,802,....,1200]
indices_to_remove_3 : [1600,1601,1602,....., 1800]

P.S:数字是任意和随机的；此外，我可能会遇到3个或更少的子集.

P.S: The numbers are arbitrary and random; moreover, I may encounter more than 3 subsets or less.

推荐答案

另一种方法是使用 more_itertools.consecutive_groups :(以@Stephen的列表为例):

Another way is using more_itertools.consecutive_groups: (used @Stephen's list for an example):

import more_itertools as mit
for group in mit.consecutive_groups(indices_to_remove):
    print(list(group))

---

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90]
[160, 161, 162, 163, 164, 165, 166, 167, 168, 169, 170]

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