将 python 列表拆分为其他“子列表"；即较小的列表 [英] Split a python list into other "sublists" i.e smaller lists

问题描述

我有一个长达 1000 个的 python 列表.类似的东西:

I have a python list which runs into 1000's. Something like:

data=["I","am","a","python","programmer".....]

其中，len(data)= 说 1003

where, len(data)= say 1003

我现在想通过将原始列表分成 100 个块来创建此列表(数据)的子集.所以，最后，我想要像这样:

I would now like to create a subset of this list (data) by splitting the orginal list into chunks of 100. So, at the end, Id like to have something like:

data_chunk1=[.....] #first 100 items of list data
data_chunk2=[.....] #second 100 items of list data
.
.
.
data_chunk11=[.....] # remainder of the entries,& its len <=100, len(data_chunk_11)=3

有没有pythonic的方法来完成这个任务?显然我可以使用 data[0:100] 等等，但我假设这非常非 Pythonic 并且非常低效.

Is there a pythonic way to achieve this task? Obviously I can use data[0:100] and so on, but I am assuming that is terribly non-pythonic and very inefficient.

非常感谢.

推荐答案

我想说

chunks = [data[x:x+100] for x in range(0, len(data), 100)]

如果你使用的是 python 2.x 而不是 3.x，你可以通过使用 xrange() 来提高内存效率，将上面的代码改为:

If you are using python 2.x instead of 3.x, you can be more memory-efficient by using xrange(), changing the above code to:

chunks = [data[x:x+100] for x in xrange(0, len(data), 100)]

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