在Lua中,如何将表用作varargs(...)? [英] in Lua, how can I use a table as varargs (...)?
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问题描述
strjoin接受一个字符串,然后接受可变数量的参数.我正在寻找一种方法,以获取具有可变数量参数的表,并将表中的每个项目用作另一个参数.
strjoin accepts one string and then a variable number of arguments. I'm looking for a way to take a table with a variable number of arguments and use each item in the table as another argument.
local myTable = {
'a',
'b',
'c',
}
-- This is what I want except that I don't want to hard code
-- a specific number of parameters
local myString = strjoin(' ', myTable[1], myTable[2], myTable[3])
推荐答案
Newer versions of Lua place the unpack function in the table module:
local myString = strjoin(' ', table.unpack(myTable))
这不能直接回答您的问题,但正如 lhf 指出的那样,以下方法效率更高:
This doesn't answer your question directly, but as lhf pointed out, the following is much more efficient:
local myString = table.concat(myTable, ' ')
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