如何检查在Lua的字符串中是否找到匹配的文本? [英] How to check if matching text is found in a string in Lua?

问题描述

如果在文本字符串中至少找到一次特定的匹配文本，例如:

I need to make a conditional that is true if a particular matching text is found at least once in a string of text, e.g.:

str = "This is some text containing the word tiger."
if string.match(str, "tiger") then
    print ("The word tiger was found.")
else
    print ("The word tiger was not found.")

如何检查文本是否在字符串中找到?

How can I check if the text is found somewhere in the string?

推荐答案

您可以使用string.match或string.find中的任何一个.我本人亲自使用 string.find() .另外，您需要指定if-else语句的end.因此，实际代码如下:

You can use either of string.match or string.find. I personally use string.find() myself. Also, you need to specify end of your if-else statement. So, the actual code will be like:

str = "This is some text containing the word tiger."
if string.match(str, "tiger") then
  print ("The word tiger was found.")
else
  print ("The word tiger was not found.")
end

或

str = "This is some text containing the word tiger."
if string.find(str, "tiger") then
  print ("The word tiger was found.")
else
  print ("The word tiger was not found.")
end

---

应注意，当尝试匹配特殊字符(例如.()[]+-等)时，应使用%字符将它们转义为模式.因此，以匹配为例. tiger(，呼叫为:

---

It should be noted that when trying to match special characters (such as .()[]+- etc.), they should be escaped in the patterns using a % character. Therefore, to match, for eg. tiger(, the call would be:

str:find "tiger%("

有关模式的更多信息，请访问 Lua-Users Wiki 或 SO的文档部分.

More information on patterns can be checked at Lua-Users wiki or SO's Documentation sections.

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