将字符串分成26个字符或更少的字符分成表格，四舍五入到最接近的单词 [英] Split string into table in groups of 26 characters or less, rounded to the nearest word

问题描述

我正在尝试将一个字符串分割成一个表，每个索引最多包含26个字符，但单词未在两个索引之间分割.如果它在单词中间延伸超过26个字符，则该单词在下一个索引中.

I'm trying to take a string and split it into a table, with each index containing a maximum of 26 characters, but words are not split between indices. If it stretches over 26 characters mid-word, that word is in the next index.

推荐答案

长于wrap_length的单词是唯一会溢出的单词，但是可以通过替换or str:find'%s'来自定义该行为.

Words longer than wrap_length are the only words that will overflow, but that behavior can be customized by replacing or str:find'%s'.

local function wrap_string(str, wrap_length)
  local lines = {}

  while #str > 0 do
    local last_space_index

    -- Only check substrings longer than the wrap length
    if #str > wrap_length then
      -- Check for first space so words longer than `wrap_length` don't break.
      last_space_index = str:sub(1, wrap_length):find'%s%S*$' or str:find'%s'
    end

    table.insert(lines, str:sub(1, last_space_index))

    if not last_space_index then break end

    str = str:sub(last_space_index + 1)
  end
  return lines
end

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