如何在Mac OS X上发现*逻辑*内核的数量? [英] How to discover number of *logical* cores on Mac OS X?

问题描述

当您运行Mac OS X时，如何从命令行得知计算机上有多少个内核?在Linux上，我使用:

How can you tell, from the command line, how many cores are on the machine when you're running Mac OS X? On Linux, I use:

x=$(awk '/^processor/ {++n} END {print n+1}' /proc/cpuinfo)

这不是完美的，但是很接近.打算将其馈送到make，这就是为什么它得出的结果比实际数字高1的原因.而且我知道上面的代码可以用Perl编写得更密集，也可以使用grep，wc和cut来编写，但是我认为上面的代码在简洁性和可读性之间取得了很好的权衡.

It's not perfect, but it's close. This is intended to get fed to make, which is why it gives a result 1 higher than the actual number. And I know the above code can be written denser in Perl or can be written using grep, wc, and cut, but I decided the above was a good tradeoff between conciseness and readability.

非常晚的为了澄清一下:我要问有多少逻辑内核可用，因为这与我想要make进行的同时作业数量相对应产生.克里斯·劳埃德(Chris Lloyd)进一步完善了jkp的答案，这正是我所需要的. YMMV.

VERY LATE Just to clarify: I'm asking how many logical cores are available, because this corresponds with how many simultaneous jobs I want make to spawn. jkp's answer, further refined by Chris Lloyd, was exactly what I needed. YMMV.

推荐答案

您可以使用 sysctl 实用程序:

sysctl -n hw.ncpu

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