如何在距系统栏一定距离的地方打开NSPopover? [英] How to open a NSPopover at a distance from the system bar?

问题描述

我正在状态栏中通过图标打开NSPopover.

I'm opening a NSPopover with the action of an icon in the status bar.

myPopover.show(relativeTo: button.bounds, of: button, preferredEdge: NSRectEdge.minY)

除了弹出窗口和系统栏的距离为零之外，这可以很好地工作:

This works fine with the exception that the distance from the popover and the system bar is zero:

我想要获得与Dropbox应用相同的结果，该应用将弹出窗口呈现在距离系统栏一小段距离的地方:

I'd like to achieve the same result as the Dropbox app which renders the popover at a small distance from the system bar:

我尝试使用button.bounds.offsetBy(dx: 0.0, dy: 20.0)，它不影响弹出窗口的位置，而button.bounds.offsetBy(dx: 0.0, dy: -20.0)则将弹出窗口置于系统栏上方:

I've tried using button.bounds.offsetBy(dx: 0.0, dy: 20.0) which doesn't affect the position of the popover and button.bounds.offsetBy(dx: 0.0, dy: -20.0) which puts the popover above the system bar:

那么如何将NSPopover放置在距系统栏一定距离的地方?

So how can I position the NSPopover at some distance from the system bar?

推荐答案

首先，button.bounds.offsetBy(dx: 0.0, dy: -20.0)无效的原因是，这些坐标落在状态栏项目本身即状态栏项目的窗口"之外.所以它外面的任何东西都被裁剪掉了.

First, the reason why button.bounds.offsetBy(dx: 0.0, dy: -20.0) didn't work is because those coordinate fell outside the "window" of the status bar item which is the status bar itself. So anything outside of it was cropped.

我通过在各处收集信息解决了这个问题:

I solved this problem by collecting information here and there:

1. 创建一个不可见的窗口.
2. 在状态栏项目的屏幕中找到坐标，并将不可见的窗口置于其下方.
3. 相对于不可见窗口而不是状态栏项目显示NSPopover.

红色的东西是不可见的窗口(出于演示目的).

The red thing is the invisible window (for demonstration purposes).

// Create a window
let invisibleWindow = NSWindow(contentRect: NSMakeRect(0, 0, 20, 5), styleMask: .borderless, backing: .buffered, defer: false)
invisibleWindow.backgroundColor = .red
invisibleWindow.alphaValue = 0

if let button = statusBarItem.button {
    // find the coordinates of the statusBarItem in screen space
    let buttonRect:NSRect = button.convert(button.bounds, to: nil)
    let screenRect:NSRect = button.window!.convertToScreen(buttonRect)

    // calculate the bottom center position (10 is the half of the window width)
    let posX = screenRect.origin.x + (screenRect.width / 2) - 10
    let posY = screenRect.origin.y

    // position and show the window
    invisibleWindow.setFrameOrigin(NSPoint(x: posX, y: posY))
    invisibleWindow.makeKeyAndOrderFront(self)

    // position and show the NSPopover
    mainPopover.show(relativeTo: invisibleWindow.contentView!.frame, of: invisibleWindow.contentView!, preferredEdge: NSRectEdge.minY)
    NSApp.activate(ignoringOtherApps: true)
}

我正在尝试使用show(relativeTo: invisibleWindow.frame ...)，并且没有显示弹出窗口，因为NSWindow不是NSView.为了显示弹出窗口，必须通过视图.

I was trying to use show(relativeTo: invisibleWindow.frame ...) and the popup wasn't showing up because NSWindow is not an NSView. For the popup to be displayed a view has to be passed.

这篇关于如何在距系统栏一定距离的地方打开NSPopover?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！