使用bazel构建Makefile [英] Building Makefile using bazel

问题描述

我正在尝试在bazel项目中构建子模块的Makefile.我看到bazel确实提供了执行bash命令的规则.我目前面临两个问题-

I am trying to build Makefile of a submodule in a bazel project. I see that bazel does provide genrule to execute bash command. I am facing two issues currently -

1.如何在执行命令之前将CD插入目录，例如-

genrule(
    name = "hello-make",
    srcs = ["hello"] + glob(["hello/**"]),
    outs = ["hello/main"],
    cmd = "(cd $(location :hello) && make)",
)

2.在执行genrule之前如何更新更新子模块?

添加cmd = "(git submodule init && git submodule update)"给出fatal: Not a git repository (or any of the parent directories): .git

复制步骤:

1. git clone [e-mail]:bazelbuild/examples.git
2. cd examples/ && git submodule add [e-mail]:mucsi96/cpp-hello-world.git cpp-tutorial/stage1/main/hello
3. cd cpp-tutorial/stage1/ && bazel build //main:hello-world

1. git clone [e-mail]:bazelbuild/examples.git
2. cd examples/ && git submodule add [e-mail]:mucsi96/cpp-hello-world.git cpp-tutorial/stage1/main/hello
3. cd cpp-tutorial/stage1/ && bazel build //main:hello-world

此步骤之后，我想添加一条规则，该规则允许我进行初始化，更新并制作hello子模块.

After this step I want to add a rule that allows me init, update and make the hello submodule.

是否有比将其创建为git clone [e-mail]:bazelbuild/examples.git的子模块更好的方法来构建[e-mail]:mucsi96/cpp-hello-world.git?

Is there a better way to build [e-mail]:mucsi96/cpp-hello-world.git than creating it as a submodule of git clone [e-mail]:bazelbuild/examples.git?

实际项目更加复杂，并且无法为cpp-hello-world.git创建BUILD文件.

The actual projects are more complex and creating a BUILD file for cpp-hello-world.git is not feasible.

推荐答案

而不是滚动自己的genrule来构建使用Makefile的(大概是C ++)项目，请查看

Instead of rolling your own genrule to build a (presumably C++) project that uses a Makefile, check out rules_foreign_cc instead. rules_foreign_cc is used by envoy and other various large C++ programs to build external CMake and Make based dependencies.

请参见 simple_make 示例.在其中，您首先要创建一个filegroup来收集与要构建的项目相关的所有源和文件，包括Makefile本身:

See the simple_make example. In it, you would first make a filegroup to collect all the sources and files related to the project to be built, including the Makefile itself:

filegroup(
    name = "sources",
    srcs = glob(["**"]),
    visibility = ["//simple_make:__subpackages__"],
)

然后，调用rules_foreign_cc的 规则，它还带有其他make特定的属性，例如prefix，make_env_vars，甚至还有一种用make_commands覆盖整个make命令的方式.在此示例中，我们仅使用lib_source和static_libraries属性:

Then, call rules_foreign_cc's make rule, which also comes with other make-specific attributes like prefix, make_env_vars, and even a way to override the entire make command with make_commands. In this example, we're just using the lib_source and static_libraries attributes:

load("@rules_foreign_cc//tools/build_defs:make.bzl", "make")

make(
    name = "make_lib",
    lib_source = "//simple_make/code:sources",
    static_libraries = ["liba.a"],
)

最后，运行bazel build //package/to:make_lib调用make规则.

在执行genrule之前如何更新更新子模块?

How do I update update submodule before executing genrule?

不要尝试执行此操作，尤其是当它更新就地项目源时. genrules和其他规则不应在构建过程中修改源的状态，而应仅构建输出文件.考虑在构建之前运行单独的脚本来更新子模块.

Try not to do this especially if it updates the sources of the project in-place. genrules and other rules should not modify the state of your sources during a build, but instead only build output files. Consider running a separate script to update submodules prior to the build.

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