在Python中，如何按已排序的键顺序遍历字典? [英] In Python, how do I iterate over a dictionary in sorted key order?

问题描述

有一个现有的函数以下面的结尾，其中d是一个字典:

There's an existing function that ends in the following, where d is a dictionary:

return d.iteritems()

返回给定字典的未排序迭代器.我想返回一个迭代器，该迭代器遍历按键排序的项目.我该怎么办?

that returns an unsorted iterator for a given dictionary. I would like to return an iterator that goes through the items sorted by key. How do I do that?

推荐答案

此功能尚未进行广泛测试，但可以在Python 2.5.2中使用.

Haven't tested this very extensively, but works in Python 2.5.2.

>>> d = {"x":2, "h":15, "a":2222}
>>> it = iter(sorted(d.iteritems()))
>>> it.next()
('a', 2222)
>>> it.next()
('h', 15)
>>> it.next()
('x', 2)
>>>

如果您习惯于使用for key, value in d.iteritems(): ...而不是迭代器，则仍然可以使用上述解决方案

If you are used to doing for key, value in d.iteritems(): ... instead of iterators, this will still work with the solution above

>>> d = {"x":2, "h":15, "a":2222}
>>> for key, value in sorted(d.iteritems()):
>>>     print(key, value)
('a', 2222)
('h', 15)
('x', 2)
>>>

对于Python 3.x，使用d.items()而不是d.iteritems()返回迭代器.

With Python 3.x, use d.items() instead of d.iteritems() to return an iterator.

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