按字典顺序对字符串排序python [英] Sort a string in lexicographic order python

问题描述

我想按字典顺序将字符串排序为列表

I want to sort a string to a list in lexicographic order as

str='aAaBbcCdE'

到

['A','a','a','B','b','C','c','d','E']

但是sorted()给我这个输出:

['A','B','C','E','a','a','b','c','d']

如何按字典顺序排序?

推荐答案

当有内置函数可以使用时，请不要使用lambda函数.也不要使用sorted的cmp参数，因为它已被弃用:

Do not use lambda functions when there's builtin ones for the job. Also never use the cmp argument of sorted because it's deprecated:

sorted(s, key=str.lower)

或

sorted(s, key=str.upper)

但这可能无法使"A"和"a"保持顺序，所以:

But that may not keep 'A' and 'a' in order, so:

sorted(sorted(s), key=str.upper)

这将并且根据sorted的性质，对于几乎排序的列表(第二个sorted)，该操作将非常快.

that will and, by the nature of sorted the operation will be very fast for almost sorted lists (the second sorted).

这篇关于按字典顺序对字符串排序python的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！