按字母顺序对二维字符串数组进行排序 [英] Sorting 2D array of strings in alphabetical order

问题描述

请帮忙，我在如何对两列中的字符串数组进行排序时遇到了问题.所以，我有两列:它们都包含一个字符串.我需要按字母顺序对第一列进行排序，而第二列不应该乱序，因此，它应该与排序后的第一列相对应.

Please help, I'm having trouble how to sort Array of Strings in two columns. So, I have two columns: Both of it contains a string. I need to sort the first column in alphabetical order while the second column should not shuffle, thus, it should correspond to the first column after sorting.

谁能看到我需要在下面的代码中放置排序方法的位置:

Can anyone see where I need to put sorting method in my code below:

public static void main(String[] args) {
    String[][] emp = {
            {"Victor    ", "ZSA"},
            {"Fred    ", "HAN"},
            {"Drake   ", "SOL"},
            {"Albert  ", "TUR"},
            {"Eric    ", "CAN"}};

    System.out.println("String 1:    String 2: ");
    for (int i = 0; i < emp.length; i++) {
        for (int j = 0; j < emp[0].length; j++) {
            System.out.printf("%9s", emp[i][j]);
        }
        System.out.println();
    }
}

输出应该是:

Albert  TUR
Drake   SOL
Eric    CAN
Fred    HAN
Victor  ZSA

推荐答案

您可以创建实现接口的自定义比较器 Comparator 将 String[] 数组(数组 2D 行)作为参数并比较两个数组的第一个元素如下所示:

You can create a custom comparator implementing the interface Comparator that takes the String[] arrays (array 2D rows) as argument and comparing the first elements of the two arrays like below:

public class CustomComparator implements Comparator<String[]> {
    @Override
    public int compare(String[] row1, String[] row2) {
        return row1[0].compareTo(row2[0]);
    }
}

在你的 main 方法中执行排序后:

After you can execute the sorting in your main method:

public static void main(String[] args) {
    String[][] emp = {
            {"Victor    ", "ZSA"},
            {"Fred    ", "HAN"},
            {"Drake   ", "SOL"},
            {"Albert  ", "TUR"},
            {"Eric    ", "CAN"}};

    Arrays.sort(emp, new CustomComparator());

    System.out.println("String 1:    String 2: ");
    for (int i = 0; i < emp.length; i++) {
        for (int j = 0; j < emp[0].length; j++) {
            System.out.printf("%9s", emp[i][j]);
        }
        System.out.println();
    }
}

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