如何按字母顺序对字符串中包含日期的数组进行排序？ [英] How to sort the Array that contains date in strings in descending order?

问题描述

我想按降序对包含日期字符串的数组进行排序，我已尝试过SO答案，但输出错误。

I want to sort the array that contains date string in descending order, I have tried SO answers, but I am getting wrong output.

请参阅下面的代码：

NSArray *dateArray=[NSArray arrayWithObjects:@"01/12/2012",@"01/26/2011",@"02/09/2005",@"02/24/2006",@"03/19/2007",@"07/14/2011",@"08/17/2007",@"10/04/2007",@"10/31/2006",@"12/05/2012",@"12/06/2006",@"12/23/2008",nil];
NSDateFormatter *formatter=[[NSDateFormatter alloc]init];
[formatter setDateFormat:@"MM/DD/YYYY"];
NSMutableArray *tempArr=[[NSMutableArray alloc]init];
for (int i=0; i<[dateArray count]; i++) {

    NSString *dt=[dateArray objectAtIndex:i];
    NSDate *newDt=[formatter dateFromString:dt];
    [tempArr addObject:newDt];
}
NSLog(@"tempArr is %@",tempArr);

我得到如下控制台输出：

I am getting Console output like as below:

2013-08-27 15：29：50.418样本[3688：c07] tempArr是（
2011-12-24 18:30:00 +0000，
2010-12-18 18:30:00 +0000，
2004-12-18 18:30:00 +0000，
2005-12-24 18:30： 00 +0000，
2006-12-23 18:30:00 +0000，
2010-12-18 18:30:00 +0000，
2006- 12-23 18:30:00 +0000，
2006-12-23 18:30:00 +0000，
2005-12-24 18:30:00 +0000，
2011-12-24 18:30:00 +0000，
2005-12-24 18:30:00 +0000，
2007-12-22 18： 30:00 +0000
）

2013-08-27 15:29:50.418 sample[3688:c07] tempArr is ( "2011-12-24 18:30:00 +0000", "2010-12-18 18:30:00 +0000", "2004-12-18 18:30:00 +0000", "2005-12-24 18:30:00 +0000", "2006-12-23 18:30:00 +0000", "2010-12-18 18:30:00 +0000", "2006-12-23 18:30:00 +0000", "2006-12-23 18:30:00 +0000", "2005-12-24 18:30:00 +0000", "2011-12-24 18:30:00 +0000", "2005-12-24 18:30:00 +0000", "2007-12-22 18:30:00 +0000" )

我不知道为什么12将在月份来临还有日期格式不像我指定的格式。

I don't know why "12" is coming in the place of Month and also the date format not coming like the format I specified.

推荐答案

嗯，首先，你实际上并没有对任何东西进行排序在你的代码中...

Well, first off, you're not actually sorting anything in your code...

你应该做这样的事情......

You should do something like this...

// create the string array
NSArray *dateArray = @[@"01/12/2012", @"01/26/2011", @"02/09/2005", @"02/24/2006", @"03/19/2007", @"07/14/2011", @"08/17/2007", @"10/04/2007", @"10/31/2006", @"12/05/2012", @"12/06/2006", @"12/23/2008"];

// create the date formatter with the correct format
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"MM/dd/yyyy"];

NSMutableArray *tempArray = [NSMutableArray array];

// fast enumeration of the array
for (NSString *dateString in dateArray) {
    NSDate *date = [formatter dateFromString:dateString];
    [tempArray addObject:date];
}

// sort the array of dates
[tempArray sortUsingComparator:^NSComparisonResult(NSDate *date1, NSDate *date2) {
    // return date2 compare date1 for descending. Or reverse the call for ascending.
    return [date2 compare:date1];
}];

NSLog(@"%@", tempArray);

编辑进入串联阵列

NSMutableArray *correctOrderStringArray = [NSMutableArray array];

for (NSDate *date in tempArray) {
    NSString *dateString = [formatter stringFromDate:date];
    [correctOrderStringArray addObject:dateString];
}

NSLog(@"%@", correctOrderStringArray);

另外，请阅读更多关于 NSDate 的信息， NSString 和 NSDateFormatter 。特别是他们如何互相交流。

Also, read up more about NSDate, NSString and NSDateFormatter. Especially how they interact with each other.

NSDate 是一个时间点。它不（并且从不）包含任何格式信息。

NSDate is a point in time. It does not (and never does) contain any formatting information.

NSDateFormatter 不包含任何有关a的信息具体日期（即时间点）。它用于获取日期并根据您提供的 NSDate 和格式生成字符串。

NSDateFormatter doesn't hold any information about a specific date (i.e. point in time). It is used to take a date and produce a string based on the NSDate and the format that you give it.

https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSDate_Class/Reference/Reference.html

https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSDateFormatter_Class/Reference/Reference.html

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