在python中设置字典中的属性 [英] Set attributes from dictionary in python
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问题描述
是否可以通过python中的字典创建对象,使得每个键都是该对象的属性?
Is it possible to create an object from a dictionary in python in such a way that each key is an attribute of that object?
类似这样的东西:
d = { 'name': 'Oscar', 'lastName': 'Reyes', 'age':32 }
e = Employee(d)
print e.name # Oscar
print e.age + 10 # 42
我认为这与该问题几乎完全相反:来自对象的字段
I think it would be pretty much the inverse of this question: Python dictionary from an object's fields
推荐答案
当然,是这样的:
class Employee(object):
def __init__(self, initial_data):
for key in initial_data:
setattr(self, key, initial_data[key])
更新
正如布伦特·纳什(Brent Nash)所建议的那样,您还可以通过允许使用关键字参数来使其更加灵活:
As Brent Nash suggests, you can make this more flexible by allowing keyword arguments as well:
class Employee(object):
def __init__(self, *initial_data, **kwargs):
for dictionary in initial_data:
for key in dictionary:
setattr(self, key, dictionary[key])
for key in kwargs:
setattr(self, key, kwargs[key])
然后您可以这样称呼它:
Then you can call it like this:
e = Employee({"name": "abc", "age": 32})
或类似这样:
e = Employee(name="abc", age=32)
甚至是这样:
employee_template = {"role": "minion"}
e = Employee(employee_template, name="abc", age=32)
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