压缩字典中的两个列表，但在关键字中保留重复项 [英] Zip two lists in dictionary but keep duplicates in key

问题描述

我有两个列表:

alist = ['key1','key2','key3','key3','key4','key4','key5']

blist=  [30001,30002,30003,30003,30004,30004,30005]

我想合并这些列表并将其添加到字典中.

I want to merge these lists and add them to a dictionary.

我尝试dict(zip(alist,blist))，但这给出了:

{'key3':30003，'key2':30002，'key1':30001，'key5':30005，'key4': 30004}

{'key3': 30003, 'key2': 30002, 'key1': 30001, 'key5': 30005, 'key4': 30004}

所需的字典形式是:

{'key1':30001，'key2':30002，'key3':30003，'key3':30003，'key4':30004，'key4': 30004，"key5":30005}

{'key1': 30001, 'key2': 30002, 'key3': 30003,'key3':30003, 'key4': 30004, 'key4': 30004, 'key5': 30005}

我想将重复项保留在字典中，并且不希望将值加入同一键(... key3':30003，'key3':30003，...).可以吗?

I want to keep the duplicates in the dictionary as well as not join the values in the same key (... key3': 30003,'key3':30003,... ).Is it possible?

谢谢.

推荐答案

您不能这样做，因为dict对象具有唯一键.您应该只使用元组的列表:

You can not do that as dict objects have unique keys. You should just the use list of tuple:

>>> alist = ['key1','key2','key3','key3','key4','key4','key5']
>>> blist=  [30001,30002,30003,30003,30004,30004,30005]

>>> zip(alist, blist)
[('key1', 30001), ('key2', 30002), ('key3', 30003), ('key3', 30003), ('key4', 30004), ('key4', 30004), ('key5', 30005)]

如果要基于键访问所有值，则可以将collections.defaultdict用作:

If you want to access all the values based on the key, you may use collections.defaultdict as:

>>> from collections import defaultdict

>>> my_dict = defaultdict(list)
>>> for k, v in zip(alist, blist):
...     my_dict[k].append(v)
...
>>> my_dict
defaultdict(<type 'list'>, {'key3': [30003, 30003], 'key2': [30002], 'key1': [30001], 'key5': [30005], 'key4': [30004, 30004]})

您可以访问defaultdict，类似于普通的dict对象.例如:

You can access defaultdict similar to normal dict objects. For example:

>>> my_dict['key3']
[30003, 30003]

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