将C类型uuid_t用作std :: map中的键的最佳方法是什么? [英] what is the best way to use the C type uuid_t as a key in a std::map?

问题描述

这是在地图中提供唯一键的适当方法吗?换句话说，键是由uuid中包含的唯一值构成的，还是由指向uuid_t结构的指针构成的?附带的问题是，当我不关心容器内按键的排序方式时，是否有一个效率更高的容器?

Is this an appropriate way to provide unique keys in a map? In other words, is the key being made from the unique value contained in the uuid, or is it being made from the pointer to the uuid_t struct? A side question, is there a more efficient container, when I don't care about the ordering by keys inside the container?

#include <uuid/uuid.h>

int main(int argc, char **argv)
{    
   std::map<uuid_t,int> myMap;         

   uuid_t id1;
   uuid_t id2;

   uuid_generate( (unsigned char *)&id1 );  
   uuid_generate( (unsigned char *)&id2 );

   myMap[id1] = 5;
   myMap[id2] = 4;

}

推荐答案

我猜想使用第三方C结构的最佳方法是通过它们的友好函数使用它们.因此，如果您想在STL中使用uuid_t，建议您为该结构创建某种C ++接口/包装器，例如

I guess the best way of using third-party C-structures is to use them through their friendly functions. So if you wanna use uuid_t in STL, I'd suggest you to create some kind of C++ interface/wrapper to that structure like

struct Uuid {
  uuid_t uuid;
  Uuid(const Uuid &other) { uuid_copy(uuid, other.uuid); }
  Uuid(const uuid_t other_uuid) { uuid_copy(uuid, other_uuid); }
  void generateInplace() { uuid_generate(uuid); }
  static Uuid generate() { Uuid wrapped; uuid_generate(wrapped.uuid); return wrapped; }
  bool operator<(const Uuid &other) { return uuid_compare(uuid, other.uuid) < 0; }
  bool operator==(const Uuid &other) { return uuid_compare(uuid, other.uuid) == 0; }
  // ...
};

这应该使您看不到uuid_t不是结构而是指向数组的指针(即typedef unsigned char uuid_t[16])的事实.

That should hide from you the fact that uuid_t isn't structure but pointer to array (i.e. typedef unsigned char uuid_t[16]).

注意:存在 uuid库的增强版本

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