从键列表创建嵌套字典的方法 [英] Method for Creating a Nested Dictionary from a List of Keys

问题描述

我想从保存键的任意元组/列表创建一个空的嵌套字典.我正在尝试找到一种在Python中执行此操作的简单方法.看起来应该由collection defaultdict处理，但我似乎无法弄清楚.

I would like to create an empty nested dictionary from an arbitrary tuple/list that holds the keys. I am trying to find a simple way to do this in Python. It looks like something that collections defaultdict should handle but I can't seem to figure it out.

keys = ('a', 'b', 'c')

还有一个字典，最终看起来像这样:

And a dictionary that will end up looking like this:

d = {
    'a': {
          'b': {
                'c': {}
               }
          }
     }

推荐答案

我想您可以使用reduce做到这一点:

I suppose you could do it with reduce:

def subdict(sub, key):
    return { key: sub }

d = reduce(subdict, reversed(keys), {})

(在Python 3中，它是 functools.reduce .)

(In Python 3, it’s functools.reduce.)

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