从2个具有重复键的列表中创建字典 [英] Creating a dictionary from 2 lists with duplicate keys

问题描述

尽管我看到过这样的问题，即从两个列表(一个带有键的列表，另一个带有对应的值)创建了一个字典，但我想从一个列表(包含键)创建一个字典，和列表列表"(包含相应的值).

Though I have seen versions of my issue whereby a dictionary was created from two lists (one list with the keys, and the other with the corresponding values), I want to create a dictionary from a list (containing the keys), and 'lists of list' (containing the corresponding values).

我的代码示例是:

#-Creating python dictionary from a list and lists of lists:
keys = [18, 34, 30, 30, 18]
values = [[7,8,9],[4,5,6],[1,2,3],[10,11,12],[13,14,15]]
print "This is example dictionary: "
print dictionary

我期望得到的结果是:

{18:[7,8,9],34:[4,5,6],30:[1,2,3],30:[10,11,12],18:[13,14,15]}

我不需要将重复的键(30、18)与它们各自的值配对.

I do not need the repeated keys (30, 18) to be paired up with their respective values.

相反，我不断得到以下结果:

Instead, I keep getting the following result:

{18: [13, 14, 15], 34: [4, 5, 6], 30: [10, 11, 12]}

此结果缺少了我期望列表中的两个元素.

This result is missing two of the elements from my expected list.

我希望这个论坛能对您有所帮助.

I am hoping to have some help from this forum.

推荐答案

如上所述，由于字典键必须唯一，因此无法实现所需的输出.

As already mentioned, your desired output is not possible as dictionary keys must be unique.

如果您不想丢失数据，则有以下两种选择.

Below are 2 alternatives if you do not want to lose data.

元组列表

res = [(i, j) for i, j in zip(keys, values)]

# [(18, [7, 8, 9]),
#  (34, [4, 5, 6]),
#  (30, [1, 2, 3]),
#  (30, [10, 11, 12]),
#  (18, [13, 14, 15])]

列表字典

from collections import defaultdict

res = defaultdict(list)

for i, j in zip(keys, values):
    res[i].append(j)

# defaultdict(list,
#             {18: [[7, 8, 9], [13, 14, 15]],
#              30: [[1, 2, 3], [10, 11, 12]],
#              34: [[4, 5, 6]]})

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