从3个列表的zip中创建字典 [英] Сreate a dictionary from a zip of 3 lists

问题描述

我想在字典中列出3个列表:

I have 3 lists that I would like to put into a dictionary:

list1 = ['a', 'b', 'c']
list2 = [1, 2, 3]
list3 = [0.5, 0.3, 0.1]

传统上，我可以只用list1，list2

Traditionally I could create a dictionary like this with just list1, list2

my_dict = dict(zip(list1, list2))
# {'a': 1, 'b': 2, 'c': 3}

但是我想得到的是:

{'a': (1, 0.5), 'b': (2, 0.3), 'c': (3, 0.1)}

这不起作用:

my_dict = dict(list1, zip(list2, list3))

推荐答案

您需要再添加一个zip，因为dict构造函数接受tuple的列表，但不接受两个list的列表:

You need to add one more zip, since dict constructor accepts list of tuples, but not two lists:

my_dict_3 = dict(zip(list1, zip(list2, list3)))

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