在字典列表中查找max len的所有字典 [英] Finding all the dicts of max len in a list of dicts

问题描述

我有一个字典列表

ld = [{'a': 1}, {'b': 2, 'c': 3}, {'d': 4, 'e': 5}]

我需要从列表中获取长度最长的所有元素，即

I need to get all the elements with the longest length from my list, i.e.

{'b': 2, 'c': 3}和{'d': 4, 'e': 5}.

我不太了解Python，但发现:

I'm not very knowledgeable in Python but I found that:

>>> max(ld, key=len)
{'b': 2, 'c': 3}  

还有一个更好的解决方案，它返回最长字典的索引:

And, an even better solution that returns the index of the longest length dictionary:

>>> max(enumerate(ld), key=lambda tup: len(tup[1]))
(1, {'b': 2, 'c': 3})

我想使用一个返回类似

(1: {'b': 2, 'c': 3}, 2: {'d': 4, 'e': 5})

我觉得我离解决方案不远(或者也许我已经走了)，但我只是不知道如何得到它.

and I feel like I'm not far from the solution (or maybe I am) but I just don't know how to get it.

推荐答案

您可以在结构中找到最大字典的长度，然后使用列表推导:

You can find the length of the maximum dictionary in the structure, and then use a list comprehension:

ld = [{'a':1}, {'b':2, 'c':3}, {'d':4, 'e':5}]
_max = max(map(len, ld))
new_result = dict(i for i in enumerate(ld) if len(i[-1]) == _max)

输出:

{1: {'b': 2, 'c': 3}, 2: {'d': 4, 'e': 5}}

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