在嵌套字典和列表中查找所有出现的键 [英] Find all occurrences of a key in nested dictionaries and lists
问题描述
我有一本这样的字典:
{ "id" : "abcde",
"key1" : "blah",
"key2" : "blah blah",
"nestedlist" : [
{ "id" : "qwerty",
"nestednestedlist" : [
{ "id" : "xyz",
"keyA" : "blah blah blah" },
{ "id" : "fghi",
"keyZ" : "blah blah blah" }],
"anothernestednestedlist" : [
{ "id" : "asdf",
"keyQ" : "blah blah" },
{ "id" : "yuiop",
"keyW" : "blah" }] } ] }
基本上是具有嵌套列表,字典和字符串的任意深度的字典.
Basically a dictionary with nested lists, dictionaries, and strings, of arbitrary depth.
遍历此方法以提取每个"id"键的值的最佳方法是什么?我想实现与"//id"之类的XPath查询等效的功能. "id"的值始终是一个字符串.
What is the best way of traversing this to extract the values of every "id" key? I want to achieve the equivalent of an XPath query like "//id". The value of "id" is always a string.
因此,在我的示例中,我需要的输出基本上是:
So from my example, the output I need is basically:
["abcde", "qwerty", "xyz", "fghi", "asdf", "yuiop"]
顺序并不重要.
推荐答案
我发现此问题非常有趣,因为它为同一问题提供了几种不同的解决方案.我采用了所有这些功能,并使用一个复杂的字典对象对其进行了测试.我必须从测试中删除两个函数,因为它们必须有很多失败的结果,并且它们不支持将返回列表或字典作为值,我认为这是必不可少的,因为应该为几乎所有 准备一个函数. >即将到来的数据.
I found this Q/A very interesting, since it provides several different solutions for the same problem. I took all these functions and tested them with a complex dictionary object. I had to take two functions out of the test, because they had to many fail results and they did not support returning lists or dicts as values, which i find essential, since a function should be prepared for almost any data to come.
因此,我通过timeit
模块以100.000迭代的速度注入了其他函数,输出结果如下:
So i pumped the other functions in 100.000 iterations through the timeit
module and output came to following result:
0.11 usec/pass on gen_dict_extract(k,o)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - -
6.03 usec/pass on find_all_items(k,o)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - -
0.15 usec/pass on findkeys(k,o)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - -
1.79 usec/pass on get_recursively(k,o)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - -
0.14 usec/pass on find(k,o)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - -
0.36 usec/pass on dict_extract(k,o)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - -
所有功能都具有相同的搜索针(日志记录")和相同的字典对象,其结构如下:
All functions had the same needle to search for ('logging') and the same dictionary object, which is constructed like this:
o = { 'temparature': '50',
'logging': {
'handlers': {
'console': {
'formatter': 'simple',
'class': 'logging.StreamHandler',
'stream': 'ext://sys.stdout',
'level': 'DEBUG'
}
},
'loggers': {
'simpleExample': {
'handlers': ['console'],
'propagate': 'no',
'level': 'INFO'
},
'root': {
'handlers': ['console'],
'level': 'DEBUG'
}
},
'version': '1',
'formatters': {
'simple': {
'datefmt': "'%Y-%m-%d %H:%M:%S'",
'format': '%(asctime)s - %(name)s - %(levelname)s - %(message)s'
}
}
},
'treatment': {'second': 5, 'last': 4, 'first': 4},
'treatment_plan': [[4, 5, 4], [4, 5, 4], [5, 5, 5]]
}
所有功能均提供相同的结果,但时间差异非常大!函数gen_dict_extract(k,o)
是我从此处的函数改编的函数,实际上,它非常类似于Alfe的find
函数,主要区别在于,如果要传递字符串,我要检查给定的对象是否具有iteritems函数.递归期间:
All functions delivered the same result, but the time differences are dramatic! The function gen_dict_extract(k,o)
is my function adapted from the functions here, actually it is pretty much like the find
function from Alfe, with the main difference, that i am checking if the given object has iteritems function, in case strings are passed during recursion:
def gen_dict_extract(key, var):
if hasattr(var,'iteritems'):
for k, v in var.iteritems():
if k == key:
yield v
if isinstance(v, dict):
for result in gen_dict_extract(key, v):
yield result
elif isinstance(v, list):
for d in v:
for result in gen_dict_extract(key, d):
yield result
因此,此变体是此处功能中最快,最安全的.并且find_all_items
的速度慢得令人难以置信,并且与第二慢的get_recursivley
相去甚远,而除dict_extract
之外的其他速度都非常接近.函数fun
和keyHole
仅在您要查找字符串时起作用.
So this variant is the fastest and safest of the functions here. And find_all_items
is incredibly slow and far off the second slowest get_recursivley
while the rest, except dict_extract
, is close to each other. The functions fun
and keyHole
only work if you are looking for strings.
有趣的学习方式:)
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