Python:将字典与列表中的列表合并为值并对其进行计数 [英] Python: merging dictionaries with lists in lists as values and counting them

问题描述

我正在尝试编写一个可以合并两个字典(TEXT FILES！)的程序.这些词典由名词和动词组成，这些名词和动词已由另一个程序从不同的语料库中索引(然后放入文本文件中).这是这些词典的形式:

I am trying to write a program that can merge two dictionaries (TEXT FILES!). These dictionaries consist of nouns and verbs that have been indexed from different corpora by another program (and then put into a text file). This is the form of these dictionaries:

dict1 = {'strawberry': [['eat', 1]], 'family-member': [['look up', 1]], 'mall': [['search', 1]]}
dict2 = {'strawberry': [['eat', 1]], 'family-member': [['lose', 1]], 'ovation': [['receive', 1]], 'mall': [['build', 1]]}

如您所见，它们是带有键的字典，在值列表中具有列表. 现在，我试图获得如下输出:

As you can see, they're dictionaries, with keys, that have lists in lists for values. Now I'm trying to get the output like this:

finaldict = {'strawberry': [['eat', 2]], 'family-member': [['look up', 1]['lose',1]], 'mall': [['search', 1]['build', 1]], 'ovation': [['receive', 1]]

直到现在，我已经能够像这样(以字符串形式)合并dict1和dict2:

Until now, I have been able to merge dict1 and dict2 like this (in a string):

{'strawberry': [['eat', 1]], 'family-member': [['look up', 1]], 'mall': [['search',
1]], 'strawberry': [['eat', 1]], 'family-member': [['lose', 1]], 'ovation':
[['receive', 1]], 'mall': [['build', 1]]}

我用下一条语句将此字符串转换为字典: finaldict = eval(str1) 它将整个事情变成一个字典，它也这样说，所以当我询问结局类型时，它不会看到像[['eat'，1]]这样的语句作为值或任何东西.我需要这个，所以我可以遍历每个项目并计算该动词出现多少次.

I convert this string as a dictionary with the next statement: finaldict = eval(str1) it turns the whole thing into a dictionary, it also says so when I ask for the type of finaldict, but it won't see the statements like [['eat', 1]] as values or anything. I need this so I can loop over every item and count how many times it appears with which verb.

推荐答案

from collections import Counter

dict1 = {'strawberry': [['eat', 1]], 'family-member': [['look up', 1]], 'mall': [['search', 1]]}
dict2 = {'strawberry': [['eat', 1]], 'family-member': [['lose', 1]], 'ovation': [['receive', 1]], 'mall': [['build', 1]]}
result = {k: Counter(dict(v)) for k, v in dict1.items()}
for k, v in dict2.items():
    result.setdefault(k, Counter()).update(dict(v))

result = {k: [list(x) for x in v.items()] for k, v in result.items()}

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