根据列表中的键对字典列表进行排序 [英] sort list of dictionaries based on keys inside the list

问题描述

如何根据dictionary中的key对此进行排序?

How can I sort this based on the key in dictionary?

df1 = [('f', {'abe': 1}), ('f', {'tbeli': 1}), ('f', {'mos': 1}), ('f', {'esc': 1})]

我尝试过

L1 = [year for (title, year) in (sorted(df1.items(), key=lambda t: t[0]))]

我想要

df1 = [('f', {'abe': 1}), ('f', {'esc': 1}), ('f', {'mos': 1}), ('f', {'tbeli': 1})]

谢谢

推荐答案

您可以有一个单独的函数来获取可迭代项中的唯一项:

You could have a separate function to get the only item in an iterable:

def only(iterable):
    x, = iterable
    return x

数字是键的可迭代项:

>>> only({'abe': 1})
'abe'

>>> only({'tbeli': 1})
'tbeli'

因此您可以将其用于排序:

so you can use it for your sort:

sorted(df1, key=lambda t: only(t[1]))

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