根据键名不同的值对字典列表进行排序 [英] Sort list of dictionaries based on values where keys have different names

问题描述

我有一个字典列表，如下所示:

I have a list of dictionaries which look like the following:

my_list = [
          {'1200' : [10, 'A']},
          {'1000' : [24, 'C']},
          {'9564' : [6, 'D']},
          ]

列表中的所有词典都有一对键值对.

All dictionaries in the list have one key-value pair.

我想根据每个字典值的第一个元素(列表)对它进行排序，因此排序后的列表看起来像:

I want to sort it based on the first element of each dictionaries value which is a list, so the sorted list would look like:

my_list_sorted = [
          {'9564' : [6, 'D']},
          {'1200' : [10, 'A']},
          {'1000' : [24, 'C']},
          ]

如您所见，这些键具有不同的名称，这就是为什么我无法使用以下帖子中的答案的原因:

As you can see the keys have different names and that's why I could not use answers from, for example, the following post: How do I sort a list of dictionaries by a value of the dictionary?

推荐答案

您可以使用values()访问dict元素:

sorted(my_list, key=lambda x: x.values()[0][0])

输出:

[
  {'9564': [6, 'D']},
  {'1200': [10, 'A']},
  {'1000': [24, 'C']}
]

这假定每个条目都包含一个至少包含一个元素的列表.

This assumes that each entry contains a list with at least one element.

编辑PYTHON 3

正如@cᴏʟᴅsᴘᴇᴇᴅ指出的那样，values()不会在python3中返回列表，因此您必须这样做:

As @cᴏʟᴅsᴘᴇᴇᴅ points out, values() does not return a list in python3, so you'll have to do:

sorted(my_list, key=lambda x: list(x.values()[0])[0])

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