根据密钥对Python字典进行排序? [英] Sorting Python Dictionary based on Key?

问题描述

我创建了一个python字典，其中包含以下形式的键:

I have created a python dictionary which has keys in this form :

11, 10, 00, 01, 20, 21, 31, 30

键是字符串

我想按以下顺序维护字典:

I would like to maintain my dictionary in these sorted order:

00, 10, 20, 30, 01, 11, 21, 31 

这是基于键的第二个值.

This is based on the second value of the key.

我尝试了这个sorted(dict.items(), key = lambda s: s[1])，并得到了像这样的键:

I tried this sorted(dict.items(), key = lambda s: s[1]) and got the keys like:

20, 30, 21, 31, 01, 11, 10, 00

有人可以引导我吗?

推荐答案

您几乎拥有它，但关键是元组的第一项:

You almost had it, but the key is the first item of the tuple:

sorted(dict.items(), key=lambda s: s[0])

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