Python-如何根据字典的值及其键对字典进行排序 [英] Python - How to sort a dictionary based on its value as well it key
问题描述
我有一个字典，如:-
{
(1, 1): 16,
(1, 2): 16,
(1, 3): 16,
(1, 4): 16,
(2, 1): 24,
(2, 2): 24,
(2, 3): 24,
(2, 4): 24 }
...我希望按照元组键的第二个字段以及字典的value字段对其进行排序...因此结果字典应为:-
...i want it to be ordered as per tuple key's second field as well as dictionary's value field... so result dictionary should be :-
{
(2, 1): 24,
(2, 2): 24,
(2, 3): 24,
(2, 4): 24,
(1, 1): 16,
(1, 2): 16,
(1, 3): 16,
(1, 4): 16
}
...我试图单独使用值对它进行排序，但是它弄乱了键元组的顺序....是的，所以我之后通过执行操作将其分配给列表...
... i tried sorting it with value alone but it messes the keys tuple order.... yes so i assigned it to a list afterwards by doing ...
list = sorted(unsorted_dict, key = unsorted_dict.__getitem__, reverse=True)....
很抱歉，我的回答只能部分解决我的情况...
Sorry to say but answer address my situation partially ...
我不想考虑排序的第一个值.让我说我有初始数据...
i dont want to consider first value for sorting..lets say i had initial data ....
{
(5, 1): 16,
(6, 2): 16,
(7, 3): 16,
(8, 4): 16,
(4, 1): 24,
(3, 2): 24,
(2, 3): 24,
(1, 4): 24 }
我想输出...
{
(4, 1): 24,
(3, 2): 24,
(2, 3): 24,
(1, 4): 24,
(5, 1): 16,
(6, 2): 16,
(7, 3): 16,
(8, 4): 16 }
....正如我所说，我想将元组 second 的值用于排序，而不要考虑将第一个元组的值用于排序...如果有人能够告诉，这将是一个很大的帮助..我如何从已排序的字典中将元组提取到类似..
....as i said i want to consider tuples second value for sorting and not consider at all first value for sorting...Also it would be a great help if someone can tell ..how do i extract the tuples from this sorted dictionary to a list like ..
(4，1)，(3，2)，(2，3)，(1，4)，(5，1)，(6，2)，(7，3)，(8，4)
(4, 1),(3, 2),(2, 3),(1, 4),(5, 1),(6, 2),(7, 3),(8, 4)
，因此该评论有助于获得我想要的...非常感谢...
so the comment helped to get what i wanted ...thanks a lot ...
list_sorted = sorted(unsorted_dict.items(),key=lambda x: (-x[1],x[0][1]))
for val in list_sorted:
final_list.append(val[0])
更正了键，值对，感谢@Padraic Cunningham指出
corrected the key,value pairs thanks @Padraic Cunningham for pointing it out
推荐答案
字典没有顺序，您可以对项目进行排序:
dicts have no order, you can sort the items:
d={
(1, 1): 16,
(1, 2): 16,
(1, 3): 16,
(1, 4): 16,
(2, 1): 24,
(2, 2): 24,
(2, 3): 24,
(2, 4): 24 }
from pprint import pprint as pp
pp(sorted(d.items(),key=lambda x: (-x[1],x[0])))
[((2, 1), 24),
((2, 2), 24),
((2, 3), 24),
((2, 4), 24),
((1, 1), 16),
((1, 2), 16),
((1, 3), 16),
((1, 4), 16)]
And if you really want a dict with the items in order you can create a collections.OrderedDict from the sorted items:
from collections import OrderedDict
od = OrderedDict(sorted(d.items(),key=lambda x: (-x[1],x[0])))
OrderedDict([((2, 1), 24), ((2, 2), 24), ((2, 3), 24), ((2, 4), 24), ((1, 1), 16), ((1, 2), 16), ((1, 3), 16), ((1, 4), 16)])
我们的主要排序键是每个值，通过用-否定每个值从高到低排序，然后我们与从低到高排序的键/元组断开联系.
Our primary sort key is each value, sorting from high to low by negating each value with a -, then we break ties with the key/tuple sorting from low to high.
通过元组中的第二个元素断开关系:
Break ties by second element in tuple:
pp(sorted(d.items(),key=lambda x:(-x[1],x[0][1])))
您编辑后的输出现在具有具有不同值的不同键，因此不确定如何排序.
Your edited output now has different keys with different values so not sure how sort can do that.
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