在字典列表中合并不同的键 [英] Merging different keys inside a list of dictionaries

问题描述

如果这是一个重复的问题，我事先表示歉意，我非常努力地在Stack Overflow中找到它，但未成功. 我有一本字典，像一个风箱.

I apologize in advance if this is a repeated question, I tried very hard to find it in Stack Overflow, but I was not successful. I have a list of dictionaries like the one bellow.

d1 = {'saw': ['movie', '14', 'bird', '8', 'light', '5', 'plane', '4', 'man', '4'], 
'saw': ['zit', '10', 'popcorn', '6', 'pimple', '6', 'cherry', '5', 'pill', '4'],
'evicted': ['tenant', '66', 'family', '5', 'renter', '5', 'neighbor', '4'], 
'evicted': ['dog', '9', 'teacher', '9', 'neighbor', '7', 'man', '6', 'girl', '6']}

我想根据它们的键合并不同的项目.这样它们看起来像:

I would like to merge different items,base on their key. So that they look like:

d2 = {'saw': ['movie', '14', 'bird', '8', 'light', '5', 
'plane', '4', 'man', '4', 'zit', '10', 'popcorn', '6', 'pimple', '6', 
'cherry', '5', 'pill', '4'],
'evicted': ['tenant', '66', 'family', '5', 'renter', '5', 'neighbor', '4', 
'dog', '9', 'teacher', '9', 'neighbor', '7', 'man', '6', 'girl', '6']}

我正在使用此代码，但没有所需的输出:

I am using this code, but it I am not having the desired the output:

d2 = {}
for d in d1:
    for k, v in d1 ():
        if k not in d2: d2 [k] = []
        d2 [k].append (v)
print(d2)

我想当有两个单独的词典列表要合并时，这种方法会更好.如何在列表中合并不同的键?我真的很感谢任何帮助！

I guess this works better when there are two separate lists of dictionaries to merge. How to merge different keys inside a list? I really appreciate any help on this!

推荐答案

1.如果您的d1是list可以.但是，如果您的d1是dict，则dict不能有重复的键.这是dict的基本比例.因此您的d1是非法的，将只有一个evicted/saw

1.if your d1 is a list it's ok. But if your d1 is a dict, dict cannot have duplicate keys. it is the basic proporty of dict. so your d1 is illegal, will only have one evicted/saw

2假设d1是一个列表，代码是:

2 assume d1 is a list the codes are:

for dicts in d1:
   for key, value in dicts.items():
      new_dict.setdefault(key,[]).extend(value)

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