在mongodb中将多个$ lookup与聚合一起使用 [英] Using multiple $lookup with aggregation in mongodb

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问题描述

我有三个收藏夹,

  1. _project-它包含所有项目
  2. _build-它包含所有内部版本,每个内部版本都必须属于一个项目
  3. _build.details-它包含必须属于一个广告集的广告,并且每个广告集必须属于一个广告系列,并且每个广告系列必须属于一个版本.

_project文档结构:

_project document structure:

{
    "_id" : ObjectId("58d8c501be2bee2bc0b3b081"),
    "CreatedBy" : ObjectId("58c801c606f72508d87421c6"),
    ....
    ....
},...

_build文档结构:

_build document structure:

{
    "_id" : ObjectId("58ee6c5e06f7254454a554fe"),
    "ModifiedBy" : ObjectId("58d93a98c6e7dbe94582619a"),
    "CreatedBy" : ObjectId("58d93a98c6e7dbe94582619a"),
    "ProgramId" : ObjectId("58c801b706f72508d87421c4"),
    "ProjectId" : ObjectId("58d9411ebe2bee43ec22aff6"),
    ....
    ....
},...

_build.detials文档结构:

_build.detials document structure:

{
    "_id" : ObjectId("58de834cc6e7dbe945acf890"),
    "BuildId" : ObjectId("58ef4b95c6e7dbe945ba700b"),
    "Values" : null,
    "Headers" : null,
    "Data" : {
        "Campaign Name" : "Remarketing | Remarketing | Facebook | Conversions | 03-01-2017",
        "Ad Set Name" : "Cancelled Orders_Greater than 50%-Cancelled Orders_Less than 50% | Desktop | Feed | Female | 21-65",
        "Ad Name" : "Carousel | Draw1,Excited2,Lottery5,Beach4 | S:1814082498827964 | 03-01-2017 | 70Custom Audiences | ",
        "Ad Set Run Status" : "ACTIVE",
        "Ad Status" : "ACTIVE",
        "Campaign Objective" : "Conversions",
        "Gender" : "Female",
        "Age Min" : "21",
        "Age Max" : "65",

    },
    "Status" : false,
    "CampaignName" : "Remarketing | Remarketing | Facebook | Conversions | 03-01-2017",
    "AdSetName" : "Cancelled Orders_Greater than 50%-Cancelled Orders_Less than 50% | Desktop | Feed | Female | 21-65",
    "AdName" : "Carousel | Draw1,Excited2,Lottery5,Beach4 | S:1814082498827964 | 03-01-2017 | 70Custom Audiences | ",
    "Campaign_Status" : 1,
    "Campaign_Id" : "1",
    "Adset_Status" : 1,
    "Adset_Id" : "123",
    "Ad_Status" : 1,
    "Ad_Id" : "1234"
},...

我要查询的内容:

我想从_project集合中获取所有项目,并希望针对每个项目进行构建,然后我希望针对每个项目和构建组合进行广告,广告集和广告系列及其计数.

I want to get all projects from _project collection and want builds against each of the project and then i want ads, adsets and campaigns and their count against each of the project and build combination.

想要输出类似:

{
    "ProjectId" : ObjectId("58d8c501be2bee2bc0b3b081"),
    "BuildId" : ObjectId("5a5ads501basdadsc0b3b346"),
    "uniqueAdsCount" : "25",
    "uniqueAdsetCount" : "5",
    "uniqueCampaignCount" : "2",
    "uniqueAdNames":[

     ],
    "uniqueAdSetNames":[

     ],
    "uniqueCampaignNames":[

     ]
},
{
next project
},
{
next project
}...

到目前为止我做了什么:

What i have done so far:

db.getCollection('_build').aggregate([
    {
        $lookup:{
            from: "_project",
            localField: "ProjectId",
            foreignField: "_id",
            as: "result"
        }
   },
   {
        $project:{
            _id: 0,
            BuildId: "$_id",
            ProjectId: "$result._id"
       }
   },
   {
        $lookup:{
            from: "_build.detail",
            localField: "BuildId",
            foreignField: "BuildId",
            as: "resultS2"
        }
   },
   {
        $project:{
            BuildId: "$BuildId",
            ProjectId: "$ProjectId",
            adsCount: {$size: "$resultS2.AdName"},
            adSetCount: {$size: "$resultS2.AdSetName"},
            campaignCount: {$size: "$resultS2.CampaignName"},
        }
   }
]);

我尝试添加一个小组舞台并使用$ addToSet,但是它给了我广告集中的重复项,我不知道我做错了什么:

I have tried adding a group stage and use $addToSet but its giving me duplicates in adsets, i don't know what i am doing wrong:

db.getCollection('_build').aggregate([
    {
        $lookup:{
            from: "_project",
            localField: "ProjectId",
            foreignField: "_id",
            as: "result"
        }
   },
   {
        $project:{
            _id: 0,
            BuildId: "$_id",
            ProjectId: "$result._id"
       }
   },
   {
        $lookup:{
            from: "_build.detail",
            localField: "BuildId",
            foreignField: "BuildId",
            as: "resultS2"
        }
   },
   {
        $project:{
            BuildId: "$BuildId",
            ProjectId: "$ProjectId",
            adsCount: {$size: "$resultS2"},
            ads: "$resultS2"
        }
   },
   {
        $group:{
            _id: "$BuildId",
            UniqueAds: {$addToSet: "$ads.Data.Ad Name"},
            UniqueAdsets: {$addToSet : "$ads.Data.Ad Set Name"}
        }
   }
]);

请帮助,如有任何疑问,请通知我,可能是我使用的是完全错误的方法,我是mongodb的新手.

Please help, and let me know in case of any queries, may be i am using a entirely wrong approach, i am new to mongodb.

提前谢谢!!

推荐答案

您可以使用以下汇总.

You can use the below aggregation.

$group,在每个级别获得distinct名称值,然后在$addFields中获得$size.

You $group, get distinct name values at each level followed by $size in the $addFields.

  db.getCollection('_project').aggregate([
     {$lookup:{from: "_build",localField: "_id",foreignField: "ProjectId",as:"result"}},
     {$unwind:"$result"},
     {$project:{_id:0,ProjectId:"$_id",BuildId:"$result._id"}},
     {$lookup:{from:"_build.detail",localField:"BuildId",foreignField:"BuildId",as:"resultS2"}},
     {$unwind:"$resultS2"},
     {$group:{
    _id:{ProjectId:"$ProjectId", BuildId:"$BuildId",campaignName:"$resultS2.Data.Campaign Name",adSet:"$resultS2.Data.Ad Set Name"},
    uniqueAdNames:{$addToSet:"$resultS2.Data.Ad Name"}
        }
     },
     {$addFields:{uniqueAdsCount:{$size:"$uniqueAdNames" }}},
     {$group :{
     _id:{ProjectId:"$_id.ProjectId",BuildId:"$_id.BuildId",campaignName:"$_id.campaignName"},
     uniqueAdNames:{$first:"$uniqueAdNames"},
     uniqueAdsCount:{$first:"$uniqueAdsCount"},
     uniqueAdSets:{$addToSet:"$_id.adSet"}
        }
     },
     {$addFields:{uniqueAdsetCount:{$size:"$uniqueAdSets"}}},
     {$group:{
     _id:{ProjectId:"$_id.ProjectId",BuildId:"$_id.BuildId"},
     uniqueAdNames:{$first:"$uniqueAdNames"},
     uniqueAdsCount:{$first:"$uniqueAdsCount"},
     uniqueAdSetNames:{$first:"$uniqueAdSets"},
     uniqueAdsetCount:{$first:"$uniqueAdsetCount"},
     uniqueCampaignNames:{$addToSet:"$_id.campaignName"}
        }
     },
     {$addFields:{uniqueCampaignCount:{$size : "$uniqueCampaignNames"}}}
  ])

这篇关于在mongodb中将多个$ lookup与聚合一起使用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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