在圆上转录多边形 [英] Transcribing a polygon on a circle

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本文介绍了在圆上转录多边形的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我目前正在尝试在圆内刻出十边形的对角线

i am currently try to inscribe diagonals of a decagon inside a circle

像这样

在C#中,我的方法是创建一个圆

in c# my approach would be creating a circle

e.Graphics.DrawEllipse(myPen, 0, 0, 100, 100);

并使用

 e.Graphics.DrawLine(myPen, 20, 5, 50, 50);

之后,我将绘制一个十边形多边形.

after that i would draw a decagon polygon.

目前,我一直在研究如何将圆分成10个部分/在圆的圆周上找到正确的点的坐标,因为我的数学不佳, 我想知道我如何知道圆的圆周上的下一个点,如上所示.
而且我也想问一个更好的方法来解决我的问题.

currently im stuck at how to divide the circle into 10 parts/ finding the correct coordiantes of the points on the circumference of the circles because im not good in math, i want to know how would i know the next point in a circumference of the circle the size of my circle is indicated above.
and also i want also to ask a better approach for my problem.

谢谢:)

推荐答案

仅用于磨粒和胫骨,这是一个通用实现,将X面多边形刻入传递的Rectangle中.请注意,在这种方法中,我实际上并没有计算任何绝对点.取而代之的是,我平移原点,旋转曲面,并使用固定的长度和角度仅相对于原点绘制线条.循环重复此操作以达到下面的最终结果,与在中命令海龟非常相似.徽标:

Just for grits and shins, here's a generic implementation that will inscribe an X-sided polygon into the Rectangle you pass it. Note that in this approach I'm not actually calculating any absolute points. Instead, I am translating the origin, rotating the surface, and drawing the lines only with respect to the origin using a fixed length and an angle. This is repeated in a loop to achieve the end result below, and is very similar to commanding the Turtle in Logo:

public partial class Form1 : Form
{

    PictureBox pb = new PictureBox();
    NumericUpDown nud = new NumericUpDown();

    public Form1()
    {
        InitializeComponent();

        this.Text = "Inscribed Polygon Demo";

        TableLayoutPanel tlp = new TableLayoutPanel();
        tlp.RowCount = 2;
        tlp.RowStyles.Clear();
        tlp.RowStyles.Add(new RowStyle(SizeType.AutoSize));
        tlp.RowStyles.Add(new RowStyle(SizeType.Percent, 100));
        tlp.ColumnCount = 2;
        tlp.ColumnStyles.Clear();
        tlp.ColumnStyles.Add(new ColumnStyle(SizeType.AutoSize));
        tlp.ColumnStyles.Add(new ColumnStyle(SizeType.AutoSize));
        tlp.Dock = DockStyle.Fill;
        this.Controls.Add(tlp);

        Label lbl = new Label();
        lbl.Text = "Number of Sides:";
        lbl.TextAlign = ContentAlignment.MiddleRight;
        tlp.Controls.Add(lbl, 0, 0);

        nud.Minimum = 3;
        nud.Maximum = 20;
        nud.AutoSize = true;
        nud.ValueChanged += new EventHandler(nud_ValueChanged);
        tlp.Controls.Add(nud, 1, 0);

        pb.Dock = DockStyle.Fill;
        pb.Paint += new PaintEventHandler(pb_Paint);
        pb.SizeChanged += new EventHandler(pb_SizeChanged);
        tlp.SetColumnSpan(pb, 2);
        tlp.Controls.Add(pb, 0, 1);
    }

    void nud_ValueChanged(object sender, EventArgs e)
    {
        pb.Refresh();
    }

    void pb_SizeChanged(object sender, EventArgs e)
    {
        pb.Refresh();
    }

    void pb_Paint(object sender, PaintEventArgs e)
    {
        // make circle centered and 90% of PictureBox size:
        int Radius = (int)((double)Math.Min(pb.ClientRectangle.Width, pb.ClientRectangle.Height) / (double)2.0 * (double).9);
        Point Center = new Point((int)((double)pb.ClientRectangle.Width / (double)2.0), (int)((double)pb.ClientRectangle.Height / (double)2.0));
        Rectangle rc = new Rectangle(Center, new Size(1, 1));
        rc.Inflate(Radius, Radius);

        InscribePolygon(e.Graphics, rc, (int)nud.Value);
    }

    private void InscribePolygon(Graphics G, Rectangle rc, int numSides)
    {
        if (numSides < 3)
            throw new Exception("Number of sides must be greater than or equal to 3!");

        float Radius = (float)((double)Math.Min(rc.Width, rc.Height) / 2.0);
        PointF Center = new PointF((float)(rc.Location.X + rc.Width / 2.0), (float)(rc.Location.Y + rc.Height / 2.0));
        RectangleF rcF = new RectangleF(Center, new SizeF(1, 1));
        rcF.Inflate(Radius, Radius);
        G.DrawEllipse(Pens.Black, rcF);

        float Sides = (float)numSides;
        float ExteriorAngle = (float)360 / Sides;
        float InteriorAngle = (Sides - (float)2) / Sides * (float)180;
        float SideLength = (float)2 * Radius * (float)Math.Sin(Math.PI / (double)Sides);
        for (int i = 1; i <= Sides; i++)
        {
            G.ResetTransform();
            G.TranslateTransform(Center.X, Center.Y);
            G.RotateTransform((i - 1) * ExteriorAngle);
            G.DrawLine(Pens.Black, new PointF(0, 0), new PointF(0, -Radius));
            G.TranslateTransform(0, -Radius);
            G.RotateTransform(180 - InteriorAngle / 2);
            G.DrawLine(Pens.Black, new PointF(0, 0), new PointF(0, -SideLength));
        }
    }

}

我在常规多边形计算器.

这篇关于在圆上转录多边形的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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